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Asked by Kumar Upendra Akshay Last Modified
Answer 
Career Group Institute Chd.
Gaurva
(17/81)^1/4 = (17)^1/4/(81)^1/4 =(17)^1/4/3
Let f(x)= x^1/4
f'(x)=1/4x^3/4
{f(x+∆x)-f(x)}= f'(x)*∆x
{f(x+∆x)-f(x)}=1/4x^3/4*∆x
Write 17=16+1 then put x=16 abd ∆x=1
{f(16+1)-f(16)}=1/4(16)^3/4*1
f(17)-f(16)=1/4*2^4
f(17)=1/32 + f(16)
f(17) = 1/32 + (16)^1/4
f(17) = 0.03125 + 2
(17)^1/4 = 2.03125
Approximate value of (17/81)^1/4 = 2.03125/3 = 0.677
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Delhi Career Group
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