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Overview

I am very passionate about student improvement and can teach them in a nice and simple way, till he understand's the subject and grasp the basic involved behind it. Can make subject basic stronger.

Languages Spoken

Hindi Proficient

English Proficient

Education

Jabalpur 1999

Bachelor of Science (B.Sc.)

Address

Kharghar, Mumbai, India - 400614

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Teaches

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

10

Board

State, ICSE, International Baccalaureate, IGCSE, CBSE

IB Subjects taught

Chemistry, Mathematics, Physics

CBSE Subjects taught

Science, Mathematics, Social science

ICSE Subjects taught

Chemistry, Hindi, Mathematics, Physics

IGCSE Subjects taught

Physics, Chemistry, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, Hindi, Science

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

10

Board

State, ICSE, International Baccalaureate, IGCSE, CBSE

IB Subjects taught

Chemistry, Mathematics, Physics

CBSE Subjects taught

Science, Mathematics, Social science

ICSE Subjects taught

Chemistry, Hindi, Mathematics, Physics

IGCSE Subjects taught

Physics, Chemistry, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, Hindi, Science

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 10 do you teach for?

State, ICSE, International Baccalaureate and others

2. Do you have any prior teaching experience?

Yes

3. Which classes do you teach?

I teach Class 10 Tuition and Class 9 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 10 years.

Answers by Praveen S. (8)

Answered on 21/12/2017 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

3(a-b+b-c+c-a)= 3*(0)=0
Answers 15 Comments
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Answered on 21/12/2017 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

Area of rectangle =l*b=16*8=128 cm^2
Answers 20 Comments
Dislike Bookmark

Answered on 21/12/2017 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

Mean of 100 observation is 50. So by replacing value of 50 by 150 new total will be 5100 and and new mean will be 5100/100 is 51
Answers 49 Comments
Dislike Bookmark

Answered on 21/12/2017 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

Area of parallelogram ABPD=2×area of ?ABC=2×15=30 sq cm since we know that AREA OF PARALLELOGRAM is twice the are of triangles if both have common base ad between same parallel lines
Answers 8 Comments
Dislike Bookmark

Answered on 21/12/2017 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

For Rhombus ABCD with BD, AC as diagonals of a rhombus. We know Diagonals are bisects each other at O Now ?AOB is a right angle triangle and by Pythagoras theorem AB^2=AO^2+OB^2 Given AC=40, BD=30 ,O is midpoint of AC,BD AO=20, OB=15 AB^2=(20×20)+(15×15)=400+225=625 AB=?625=25 Therefore side of the... ...more
For Rhombus ABCD with BD, AC as diagonals of a rhombus. We know Diagonals are bisects each other at O Now ?AOB is a right angle triangle and by Pythagoras theorem AB^2=AO^2+OB^2 Given AC=40, BD=30 ,O is midpoint of AC,BD AO=20, OB=15 AB^2=(20×20)+(15×15)=400+225=625 AB=?625=25 Therefore side of the rhombus is 25cm
Answers 5 Comments
Dislike Bookmark

Teaches

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

10

Board

State, ICSE, International Baccalaureate, IGCSE, CBSE

IB Subjects taught

Chemistry, Mathematics, Physics

CBSE Subjects taught

Science, Mathematics, Social science

ICSE Subjects taught

Chemistry, Hindi, Mathematics, Physics

IGCSE Subjects taught

Physics, Chemistry, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, Hindi, Science

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

10

Board

State, ICSE, International Baccalaureate, IGCSE, CBSE

IB Subjects taught

Chemistry, Mathematics, Physics

CBSE Subjects taught

Science, Mathematics, Social science

ICSE Subjects taught

Chemistry, Hindi, Mathematics, Physics

IGCSE Subjects taught

Physics, Chemistry, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, Hindi, Science

No Reviews yet!

Answers by Praveen S. (8)

Answered on 21/12/2017 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

3(a-b+b-c+c-a)= 3*(0)=0
Answers 15 Comments
Dislike Bookmark

Answered on 21/12/2017 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

Area of rectangle =l*b=16*8=128 cm^2
Answers 20 Comments
Dislike Bookmark

Answered on 21/12/2017 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

Mean of 100 observation is 50. So by replacing value of 50 by 150 new total will be 5100 and and new mean will be 5100/100 is 51
Answers 49 Comments
Dislike Bookmark

Answered on 21/12/2017 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

Area of parallelogram ABPD=2×area of ?ABC=2×15=30 sq cm since we know that AREA OF PARALLELOGRAM is twice the are of triangles if both have common base ad between same parallel lines
Answers 8 Comments
Dislike Bookmark

Answered on 21/12/2017 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

For Rhombus ABCD with BD, AC as diagonals of a rhombus. We know Diagonals are bisects each other at O Now ?AOB is a right angle triangle and by Pythagoras theorem AB^2=AO^2+OB^2 Given AC=40, BD=30 ,O is midpoint of AC,BD AO=20, OB=15 AB^2=(20×20)+(15×15)=400+225=625 AB=?625=25 Therefore side of the... ...more
For Rhombus ABCD with BD, AC as diagonals of a rhombus. We know Diagonals are bisects each other at O Now ?AOB is a right angle triangle and by Pythagoras theorem AB^2=AO^2+OB^2 Given AC=40, BD=30 ,O is midpoint of AC,BD AO=20, OB=15 AB^2=(20×20)+(15×15)=400+225=625 AB=?625=25 Therefore side of the rhombus is 25cm
Answers 5 Comments
Dislike Bookmark

Contact

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Praveen S. describes himself as Teacher. He conducts classes in Class 10 Tuition and Class 9 Tuition. Praveen is located in Kharghar, Mumbai. Praveen takes at students Home, Regular Classes- at his Home and Online Classes- via online medium. He has 10 years of teaching experience . Praveen has completed Bachelor of Science (B.Sc.) from Jabalpur in 1999. He is well versed in Hindi and English.

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