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Class 10 > Learn Mathematics > The adjacent sides of a rectangle are 16 cm and 8 cm....
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The adjacent sides of a rectangle are 16 cm and 8 cm. Find the area of the rectangle.

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128cm^2
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Length=16c.m Breadth=8c.m Area =l*b=16*8=128cm sq
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Highly Qualified Tutor

Length of the rectangle = 16 cm Breadth of the rectangle = 8 cm Area of rectangle = (l × b) = (16 × 8) = (128) Area of rectangle is 128
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Length of the rectangle = 16 cm

Breadth of the rectangle = 8 cm

 Area of rectangle = (l × b) 

                                    = (16 × 8)

                                    = (128)

 Area of rectangle is 128 

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Tutor

Given, Length=16 cm Breadth=8cm So, Area=length × breadth =16×8=128 square cm
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Tutor

The area of a rectangle is equal to the multiplication of two sides i.e. Area = 16*8 sq-cm = 128 sq-cm.
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Math Magician

Length of the rectangle = 16 cm Breadth of the rectangle = 8 cm Area of rectangle = (Length × Breadth) = (16 × 8) = 128 Area of rectangle is 128
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Length of the rectangle = 16 cm

Breadth of the rectangle = 8 cm

 Area of rectangle = (Length × Breadth) 

                                    = (16 × 8)

                                    = 128

 Area of rectangle is 128 

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Teacher

Area = 16 x 8 = 128 sqm
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Tutor

Area = (length*breath) = 16*8 = 128 cm^2.
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Maths Tutor

Rectangular shape area= l×b =16×8 =128 cm^2.
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Science Teacher

To find out the area of a rectangle you have to multiply its length with its breadth. Here, Length (L)=16 cm, and Breadth (B)=8 cm So area is, A = L*B = 16*8 = 128 sq. cm (Ans)
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