Lalaram Nagar Geeta Nagar, Indore, India - 452001.
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Hindi Mother Tongue (Native)
English Proficient
RGPV 2018
Bachelor of Engineering (B.E.)
23, Geeta Nagar Colony, Geeta Nagar, Lalaram Nagar
Lalaram Nagar Geeta Nagar, Indore, India - 452001
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
4
Board
CBSE
CBSE Subjects taught
English, Information and Comunication Technology, Social science, Mathematics, Science, Hindi
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
4
Board
CBSE
CBSE Subjects taught
English, Information and Comunication Technology, Social science, Mathematics, Science, Hindi
Taught in School or College
No
1. Which school boards of Class 10 do you teach for?
CBSE
2. Do you have any prior teaching experience?
No
3. Which classes do you teach?
I teach Class 10 Tuition and Class 9 Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a paid demo class.
5. How many years of experience do you have?
I have been teaching for 4 years.
Answered on 30/06/2018 Learn Tuition/Class VI-VIII Tuition/Mathematics
Let us assume that Ram has x no. of stamps and Ankush has y no. of stamps. Also, x = (4/5)y since Ram has 4/5 stamps as Ankush. Now, we know that
x + y = 4500 ( since total number of stamps are 4500)
And
x = (4/5)y
Seeing both the equations
(4/5)y + y = 4500
9y = 4500×5
y = (4500 × 5)/9
y = 2500 stamps.
So Ankush has 2500 stamps.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
4
Board
CBSE
CBSE Subjects taught
English, Information and Comunication Technology, Social science, Mathematics, Science, Hindi
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
4
Board
CBSE
CBSE Subjects taught
English, Information and Comunication Technology, Social science, Mathematics, Science, Hindi
Taught in School or College
No
Answered on 30/06/2018 Learn Tuition/Class VI-VIII Tuition/Mathematics
Let us assume that Ram has x no. of stamps and Ankush has y no. of stamps. Also, x = (4/5)y since Ram has 4/5 stamps as Ankush. Now, we know that
x + y = 4500 ( since total number of stamps are 4500)
And
x = (4/5)y
Seeing both the equations
(4/5)y + y = 4500
9y = 4500×5
y = (4500 × 5)/9
y = 2500 stamps.
So Ankush has 2500 stamps.
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