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Chandrakanth Class 9 Tuition trainer in Hyderabad

Chandrakanth

Engineering Tutor

Borabanda Parvathi Nagar, Hyderabad, India - 500072.

1 Student

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Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

I can teach each and every topics very easily and make it stronger for the students.

Languages Spoken

English

Telugu

Hindi

Education

Matrusree engineering college 2017

Bachelor of Technology (B.Tech.)

Address

Borabanda Parvathi Nagar, Hyderabad, India - 500072

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Teaches

Class 9 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

2

Board

State, CBSE

CBSE Subjects taught

Telugu, Science, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Science, Social Science, Telugu, Mathematics

Class 10 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

2

Board

State, CBSE

CBSE Subjects taught

Telugu, Science, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Science, Social Science, Telugu, Mathematics

BTech Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BTech Tuition

2

BTech Mechanical subjects

Strength of Materials, Machine Dynamics and Vibrations/ Acoustics, Turbomachines, Machine Design, Finite Element Analysis, Material Science and Metallurgy, Refrigeration & Air Conditioning Systems, Heat Treatment of Metals and Alloys, Automotive Fuels and Fuel Sysytems, Welding Technology, Heat & Mass Transfer, Kinematics of Machinery, Analysis and Design of Machine Components, Machine Tool Technology, Electronic Mesurement & Instrumentation, Dynamics of Machinery, Fluid Mechanics, Steam & Gas Turbines, Plant Layout and Material Handling, Composites: Mechanics & Processing, Metrology, Mechanical Measurements and Instrumentation, Operations Research, Mechanics of Machines, Internal Combustion Engines and Emissions, Jet Propulsion and Rocket Technology, Manufacturing Technology, Thermodynamics

BTech Branch

BTech 1st Year Engineering, BTech Automobile Engineering, BTech Mechanical Engineering

BTech Automobile subjects

Strength Of Materials, Engineering Mechanics, Mechanics Of Machines, Measurement And Metrology & Instrumentation, Design Of Machine Elements, Thermodynamics, Theory Of Machines

Type of class

Crash Course

Class strength catered to

One on one/ Private Tutions, Group Classes

Taught in School or College

Yes

BTech 1st Year subjects

Engineering Chemistry, Engineering Physics, Basic Electronics, Basic Mechanical Engineering, Engineering Graphics, Engineering Mathematics (M1), Mechanics Of Solids, Advanced Mathematics (M2), Environmental Studies

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 10 do you teach for?

State, CBSE

2. Do you have any prior teaching experience?

Yes

3. Which classes do you teach?

I teach BTech Tuition, Class 10 Tuition and Class 9 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 2 years.

Answers by Chandrakanth (6)

Answered on 09/02/2018 Learn CBSE/Class 10/Science +1 Tuition/Class IX-X Tuition

Q=mC?T Q= thermal energy or heat(J or KJ) m=mass(g or kg) C= specific heat capacity ?T=change in temperature( K or °C) Eg: specific heat of silicon is 703 J/Kg°C How much energy is needed to raise the temperature of a 7 kg chunk of silicon by 10°C. Solution: Q= 7 kg*( 703J/kg°c)*10&de... ...more

Q=mC?T

Q= thermal energy or heat(J or KJ)

m=mass(g or kg)

C= specific heat capacity

?T=change in temperature( K or °C)

Eg: specific heat of silicon is 703 J/Kg°C

How much energy is needed to raise the temperature of a 7 kg chunk of silicon by 10°C.

Solution:

Q= 7 kg*( 703J/kg°c)*10°c=49210J.

Tq.

Answers 1 Comments
Dislike Bookmark

Answered on 09/02/2018 Learn CBSE/Class 9/Science +1 Tuition/Class IX-X Tuition

A chemical formula of a compound is symbolic representation of its composition. A chemical formula of a compound shows its constituent elements and the number of atoms of each combining element. For eg: The chemical formula of hydrogen sulphide if H2S.it indicates that in hydrogen sulphide two hydrogen... ...more

A chemical formula of a compound is symbolic representation of its composition.

A chemical formula of a compound shows its constituent elements and the number of atoms of each combining element.

For eg: The chemical formula of hydrogen sulphide if H2S.it indicates that in hydrogen sulphide two hydrogen atoms and one sulphur atom are chemically united..

 Tq.

Answers 2 Comments
Dislike Bookmark

Answered on 09/02/2018 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

Larger angle X Smaller angle Y We have X+Y=180..(1) larger angle exceeds thrice smaller by 20 ∴X=3Y+20..(2) Solving (1)&(2) X+Y=180 X-3Y=20 4Y=160⇒Y=40... smaller angle ∴larger angle X=140 Tq. ...more

Larger angle X

Smaller angle Y

We have X+Y=180..(1)

larger angle exceeds thrice  smaller by 20

∴X=3Y+20..(2)

Solving (1)&(2)

X+Y=180

X-3Y=20

4Y=160⇒Y=40... smaller angle

∴larger angle X=140

Tq.

 

 

Answers 8 Comments
Dislike Bookmark

Answered on 07/02/2018 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

x3+ px2 +qx+2 α+β+γ=-p...(1) αβ+βγ+γα=q...(2) αγβ=-2..(3) αβ+1=0(given) From eq(3)..γ=2 2p+q+5=-2(α+β+γ)+(αβ+βγ+γα)+5 =-2(α+β+2)+(-1+2β+2α)+5 ... ...more

x3+ px2 +qx+2

α+β+γ=-p...(1)

αβ+βγ+γα=q...(2)

αγβ=-2..(3)

αβ+1=0(given)

From eq(3)..γ=2

2p+q+5=-2(α+β+γ)+(αβ+βγ+γα)+5

             =-2(α+β+2)+(-1+2β+2α)+5

             =0

∴2p+q+5=0.

 

Answers 2 Comments
Dislike Bookmark

Teaches

Class 9 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

2

Board

State, CBSE

CBSE Subjects taught

Telugu, Science, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Science, Social Science, Telugu, Mathematics

Class 10 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

2

Board

State, CBSE

CBSE Subjects taught

Telugu, Science, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Science, Social Science, Telugu, Mathematics

BTech Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BTech Tuition

2

BTech Mechanical subjects

Strength of Materials, Machine Dynamics and Vibrations/ Acoustics, Turbomachines, Machine Design, Finite Element Analysis, Material Science and Metallurgy, Refrigeration & Air Conditioning Systems, Heat Treatment of Metals and Alloys, Automotive Fuels and Fuel Sysytems, Welding Technology, Heat & Mass Transfer, Kinematics of Machinery, Analysis and Design of Machine Components, Machine Tool Technology, Electronic Mesurement & Instrumentation, Dynamics of Machinery, Fluid Mechanics, Steam & Gas Turbines, Plant Layout and Material Handling, Composites: Mechanics & Processing, Metrology, Mechanical Measurements and Instrumentation, Operations Research, Mechanics of Machines, Internal Combustion Engines and Emissions, Jet Propulsion and Rocket Technology, Manufacturing Technology, Thermodynamics

BTech Branch

BTech 1st Year Engineering, BTech Automobile Engineering, BTech Mechanical Engineering

BTech Automobile subjects

Strength Of Materials, Engineering Mechanics, Mechanics Of Machines, Measurement And Metrology & Instrumentation, Design Of Machine Elements, Thermodynamics, Theory Of Machines

Type of class

Crash Course

Class strength catered to

One on one/ Private Tutions, Group Classes

Taught in School or College

Yes

BTech 1st Year subjects

Engineering Chemistry, Engineering Physics, Basic Electronics, Basic Mechanical Engineering, Engineering Graphics, Engineering Mathematics (M1), Mechanics Of Solids, Advanced Mathematics (M2), Environmental Studies

No Reviews yet!

Answers by Chandrakanth (6)

Answered on 09/02/2018 Learn CBSE/Class 10/Science +1 Tuition/Class IX-X Tuition

Q=mC?T Q= thermal energy or heat(J or KJ) m=mass(g or kg) C= specific heat capacity ?T=change in temperature( K or °C) Eg: specific heat of silicon is 703 J/Kg°C How much energy is needed to raise the temperature of a 7 kg chunk of silicon by 10°C. Solution: Q= 7 kg*( 703J/kg°c)*10&de... ...more

Q=mC?T

Q= thermal energy or heat(J or KJ)

m=mass(g or kg)

C= specific heat capacity

?T=change in temperature( K or °C)

Eg: specific heat of silicon is 703 J/Kg°C

How much energy is needed to raise the temperature of a 7 kg chunk of silicon by 10°C.

Solution:

Q= 7 kg*( 703J/kg°c)*10°c=49210J.

Tq.

Answers 1 Comments
Dislike Bookmark

Answered on 09/02/2018 Learn CBSE/Class 9/Science +1 Tuition/Class IX-X Tuition

A chemical formula of a compound is symbolic representation of its composition. A chemical formula of a compound shows its constituent elements and the number of atoms of each combining element. For eg: The chemical formula of hydrogen sulphide if H2S.it indicates that in hydrogen sulphide two hydrogen... ...more

A chemical formula of a compound is symbolic representation of its composition.

A chemical formula of a compound shows its constituent elements and the number of atoms of each combining element.

For eg: The chemical formula of hydrogen sulphide if H2S.it indicates that in hydrogen sulphide two hydrogen atoms and one sulphur atom are chemically united..

 Tq.

Answers 2 Comments
Dislike Bookmark

Answered on 09/02/2018 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

Larger angle X Smaller angle Y We have X+Y=180..(1) larger angle exceeds thrice smaller by 20 ∴X=3Y+20..(2) Solving (1)&(2) X+Y=180 X-3Y=20 4Y=160⇒Y=40... smaller angle ∴larger angle X=140 Tq. ...more

Larger angle X

Smaller angle Y

We have X+Y=180..(1)

larger angle exceeds thrice  smaller by 20

∴X=3Y+20..(2)

Solving (1)&(2)

X+Y=180

X-3Y=20

4Y=160⇒Y=40... smaller angle

∴larger angle X=140

Tq.

 

 

Answers 8 Comments
Dislike Bookmark

Answered on 07/02/2018 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

x3+ px2 +qx+2 α+β+γ=-p...(1) αβ+βγ+γα=q...(2) αγβ=-2..(3) αβ+1=0(given) From eq(3)..γ=2 2p+q+5=-2(α+β+γ)+(αβ+βγ+γα)+5 =-2(α+β+2)+(-1+2β+2α)+5 ... ...more

x3+ px2 +qx+2

α+β+γ=-p...(1)

αβ+βγ+γα=q...(2)

αγβ=-2..(3)

αβ+1=0(given)

From eq(3)..γ=2

2p+q+5=-2(α+β+γ)+(αβ+βγ+γα)+5

             =-2(α+β+2)+(-1+2β+2α)+5

             =0

∴2p+q+5=0.

 

Answers 2 Comments
Dislike Bookmark

Contact

Load More

Chandrakanth describes himself as Engineering Tutor. He conducts classes in BTech Tuition, Class 10 Tuition and Class 9 Tuition. Chandrakanth is located in Borabanda Parvathi Nagar, Hyderabad. Chandrakanth takes at students Home and Regular Classes- at his Home. He has 2 years of teaching experience . Chandrakanth has completed Bachelor of Technology (B.Tech.) from Matrusree engineering college in 2017. HeĀ is well versed in English, Telugu and Hindi.

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