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Asked by Poonam Last Modified
Bhanu Shringi
B.tech in ECE as well as B.Ed & CTET qualified with 8+ years of experience in teaching of Physics
Given- u=0 (start from rest)
a= 0.1 m/s2, t= 2 min= 2x60 sec =120 sec
To find- a) v=? & b) s=?
Solution- a) v = u +at= 0+ 0.1x 120 = 12m/s
b) s= ut + 1/2 a (t) ² = 0 + 1/2 x0. 1x (120) ² = 720 m
Concept- Always covert all quantities in to same unit ( prefer SI units)
read lessGiven data
Initial velocity, u = 0 m/s
Acceleration , a= 0.1m/S2
Time, t = 2min= 120s
Speed acquired,
v= u +at
= 0+ 0.1x120
= 12m/s.
The speed acquired is 12m/s
Distance travelled,
S= ut + 1/2at2
= 0 + 1/2 ( 0.1x120x120)
= 0.1x120x60
= 720m
The distance travelled is 720m.
read less
Dharmendra Singh Rathore
Contact me at 6375 746627 for better conversation. Specialist for Civil Engineering and Upto 10th.
We shall use the equation
Traveled distance = ut+(1/2)at^{2}
U is the initial velocity,
t is time
a is acceleration
Here, u=0, since bus started from rest.
So,
S = (1/2)at^2
= (1/2)×0.1×120^{2}
Distance traveled after 2 mins = 720meters.
read less
View 3 more Answers
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