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A bus starting from rest moves with a uniform acceleration of 0.1 m s−2 for 2 minutes. Find (a) the speed acquired, (b) the distance travelled.
Asked by Poonam Last Modified
Answer 
Bhanu Shringi
B.tech in ECE as well as B.Ed & CTET qualified with 8+ years of experience in teaching of Physics
Given- u=0 (start from rest)
a= 0.1 m/s2, t= 2 min= 2x60 sec =120 sec
To find- a) v=? & b) s=?
Solution- a) v = u +at= 0+ 0.1x 120 = 12m/s
b) s= ut + 1/2 a (t) ² = 0 + 1/2 x0. 1x (120) ² = 720 m
Concept- Always covert all quantities in to same unit ( prefer SI units)
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Dharmendra Singh Rathore
Contact me at 6375 746627 for better conversation. Specialist for Civil Engineering and Upto 10th.
We shall use the equation
Traveled distance = ut+(1/2)at^{2}
U is the initial velocity,
t is time
a is acceleration
Here, u=0, since bus started from rest.
So,
S = (1/2)at^2
= (1/2)×0.1×120^{2}
Distance traveled after 2 mins = 720meters.
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Given data
Initial velocity, u = 0 m/s
Acceleration , a= 0.1m/S2
Time, t = 2min= 120s
Speed acquired,
v= u +at
= 0+ 0.1x120
= 12m/s.
The speed acquired is 12m/s
Distance travelled,
S= ut + 1/2at2
= 0 + 1/2 ( 0.1x120x120)
= 0.1x120x60
= 720m
The distance travelled is 720m.
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