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A racing car has a uniform acceleration of 4 m s−2. What distance will it cover in 10 s after start?

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TEACHING EXP OF MORE THAN 8 YEARS MATHEMATICS BET RESULT IS 100

if u=0 then S= ut+1/2 at^2 s=1/2*4*100= 200m
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Trained teacher, passionate about simplifying Chemistry

Given data, Initial velocity, u= 0m/s (body is starting from rest) Time, t = 10s Acceleration, a = 4ms-2 Distance covered, S, S= ut + 1/2 at2 = 0 x 10 + 1/2 ( 4x10x10) = 2x10x10 = 200m. Thus, the distance travelled is 200m
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Given data,

Initial velocity, u= 0m/s (body is starting from rest)

Time, t = 10s

Acceleration, a = 4ms-2

Distance covered, S,

S= ut + 1/2 at2

= 0 x 10 + 1/2 ( 4x10x10)

= 2x10x10

= 200m.

Thus, the distance travelled is 200m
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40m or 0.04km Speed =distance /time here distance =speed *time so, Speed =4m/s , time =10sec So distance =4*10 =40m or 40/1000km=0.04km
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The stock market is a device for transferring money from the impatient to the patient

Use formula S = ut + 1/2 at2, please 2 understand as square , where S = distance covered, u = initial speed , a = acceleration and t = time S = 0 x 10 + 1/2 x 4 x 10 x 10 = 0 + 200 = 200m
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Completed graduation in Mathematics from Calcutta University

200m
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