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A trolley, while going down an inclined plane, has an acceleration of 2 cm s−2. What will be its velocity 3 s after the start?
Asked by Anand Last Modified
Answer 
Given :
Acceleration, a = 2 cm/s^2 = 0.02 m/s^2
Initial velocity,u = 0 m/s
Time,t = 3s
To find:
Velocity after 3 s,v = ?
Solution:
The trolley is on the inclined plane,
Hence, the first equation of motion is to be applied to calculate velocity after 3 sec.
Therefore, v = u + at
v = 0 + (0.02 X 3)
v = 0.06m/s
Therefore, 0.06m/s will be the velocity of the trolley after 3s.
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Gautam Kumar
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Sachin Jadhao
Mechanical Engineer with 5 Years of Working experience and Teaching experience for more than a year
It can be solved easily by using Uniform acceleration equation: V=u+at ( where V= final velocity of the object, u = initial velocity, a = acceleration, t = time at which the velocity to be calculated)
Simply Putting the given value in equations: As initial velocity " u " is not given in the problem , assuming the trolley starts from rest, Therefore u=0, a= 2 cm /s^2 , t (given) = 3s ( given), V= final velocity after 3 sec to be calculated?
V= 0+(2x3) = 6cm/s or 0.06 m/s
Therefore Velocity after 3 sec will be 0.06 m/s
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