Konanakunte, Bangalore, India - 560062.
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Kannada Mother Tongue (Native)
Hindi Proficient
English Proficient
NITK Pursuing
Bachelor of Technology (B.Tech.)
Konanakunte, Bangalore, India - 560062
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Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
1
Board
CBSE
Preferred class strength
One on one/ Private Tutions, Group Classes
CBSE Subjects taught
English, Social science, Mathematics, Science
Experience in School or College
I taught a my father's friend's son 11th Standard Chemistry and Physics. I have taught my classmates and siblings all my life. They always come to me because I can teach them clearly and in a simple, easy-to-understand way, without compromising on depth of understanding.
Taught in School or College
Yes
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
1
Board
CBSE, State
State boards taught
Karnataka State Board
Preferred class strength
One on one/ Private Tutions, Group Classes
CBSE Subjects taught
English, Social science, Mathematics, Science
Taught in School or College
No
State Syllabus Subjects taught
Science, Social Science, Mathematics, English
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
1
Board
CBSE, State
State boards taught
Karnataka State Board
Preferred class strength
One on one/ Private Tutions, Group Classes
CBSE Subjects taught
Science, Social Science, Mathematics, English, EVS
Taught in School or College
No
State Syllabus Subjects taught
EVS, Mathematics, Science, English, Social science
1. Which school boards of Class 10 do you teach for?
CBSE
2. Do you have any prior teaching experience?
Yes
3. Which classes do you teach?
I teach Class 10 Tuition, Class 8 Tuition and Class 9 Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 1 year.
Answered on 14 Jun Learn CBSE/Class 10/Mathematics/UNIT IV: Geometry/Constructions
To divide a line segment of 7.6 cm into two parts in the ratio 5:8, the segment is divided into a total of 5+8=13 parts.
The length of each part is 7.6 cm/13 ≈0.5846cm
2.923 cm+4.677 cm≈7.6 cm
Answered on 14 Jun Learn CBSE/Class 10/Mathematics/UNIT IV: Geometry/Constructions
I'll provide a step-by-step guide on how you can draw these triangles using basic geometry tools:
Draw the Base (5 cm):
Draw an Arc (6 cm):
Draw an Arc (7 cm):
Mark the Intersection (Point C):
Complete the Triangle:
1. Calculate the Scaled Sides: The sides of the scaled triangle are 4/5 of the corresponding sides of the first triangle.
2. Measure and Draw the Scaled Sides:
Draw the Base (4 cm):
Draw a horizontal line segment DE of length 4 cm.
Draw an Arc (4.8 cm):
Draw an Arc (5.6 cm):
Mark the Intersection (Point F):
Complete the Triangle:
Answered on 14 Jun Learn CBSE/Class 9/Science/Unit 3-Motion, Force and Work/Motion
a) Average speed is defined as the total distance traveled divided by the total time taken to travel that distance. Mathematically, it can be expressed as:
Average speed=Total distance/Total time
(b) To calculate the average speed for the entire journey of the bus, we need to determine the total distance traveled and the total time taken for the round trip.
Total Distance: The bus travels a distance of 120 km to the destination and then returns the same distance back. Therefore, the total distance, D = 120km + 120km = 240km
Total Time: To find the total time, we need to calculate the time taken for each leg of the journey separately and then sum these times.
Time to travel to the destination: The bus travels 120 km with a speed of 40 km/h.
t1=Distance/Speed=120 km/40 km/h=3 hours
Time to return: The bus returns the same 120 km distance with a speed of 30 km/h.
t2=DistanceSpeed=120 km30 km/h=4 hours
Therefore, the total time,T for the round trip is:
T=t1+t2=3 hours+4 hours=7 hours
Average Speed: Using the formula for average speed: Average speed=Total distance/Total time=240 km/7 hours
Calculating this gives:
Average speed=240km/7hrs ≈ 34.29 km/h
So, the average speed for the entire journey is approximately 34.29 km/h
Answered on 14 Jun Learn CBSE/Class 10
Hi Riddhi.
I am Adithi. It's disappointing to work very hard for a certain goal and not get the result you deserve. But your 10th grades only show you marks, they cannot indicate your true capabilities.
Keep going, keep learning. Become capable, become technically strong. Then, your marks will just become a byproduct.
Just remember, becoming capable is the goal, not getting marks.
Remember, you will struggle with JEE, regardless of your marks in 10th.
I can help you prepare in a smarter and more efficient manner to help with your stress. I am personally studying at NITK and know exactly what you are going through. Reach out to me anytime. Good luck!
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
1
Board
CBSE
Preferred class strength
One on one/ Private Tutions, Group Classes
CBSE Subjects taught
English, Social science, Mathematics, Science
Experience in School or College
I taught a my father's friend's son 11th Standard Chemistry and Physics. I have taught my classmates and siblings all my life. They always come to me because I can teach them clearly and in a simple, easy-to-understand way, without compromising on depth of understanding.
Taught in School or College
Yes
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
1
Board
CBSE, State
State boards taught
Karnataka State Board
Preferred class strength
One on one/ Private Tutions, Group Classes
CBSE Subjects taught
English, Social science, Mathematics, Science
Taught in School or College
No
State Syllabus Subjects taught
Science, Social Science, Mathematics, English
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
1
Board
CBSE, State
State boards taught
Karnataka State Board
Preferred class strength
One on one/ Private Tutions, Group Classes
CBSE Subjects taught
Science, Social Science, Mathematics, English, EVS
Taught in School or College
No
State Syllabus Subjects taught
EVS, Mathematics, Science, English, Social science
Answered on 14 Jun Learn CBSE/Class 10/Mathematics/UNIT IV: Geometry/Constructions
To divide a line segment of 7.6 cm into two parts in the ratio 5:8, the segment is divided into a total of 5+8=13 parts.
The length of each part is 7.6 cm/13 ≈0.5846cm
2.923 cm+4.677 cm≈7.6 cm
Answered on 14 Jun Learn CBSE/Class 10/Mathematics/UNIT IV: Geometry/Constructions
I'll provide a step-by-step guide on how you can draw these triangles using basic geometry tools:
Draw the Base (5 cm):
Draw an Arc (6 cm):
Draw an Arc (7 cm):
Mark the Intersection (Point C):
Complete the Triangle:
1. Calculate the Scaled Sides: The sides of the scaled triangle are 4/5 of the corresponding sides of the first triangle.
2. Measure and Draw the Scaled Sides:
Draw the Base (4 cm):
Draw a horizontal line segment DE of length 4 cm.
Draw an Arc (4.8 cm):
Draw an Arc (5.6 cm):
Mark the Intersection (Point F):
Complete the Triangle:
Answered on 14 Jun Learn CBSE/Class 9/Science/Unit 3-Motion, Force and Work/Motion
a) Average speed is defined as the total distance traveled divided by the total time taken to travel that distance. Mathematically, it can be expressed as:
Average speed=Total distance/Total time
(b) To calculate the average speed for the entire journey of the bus, we need to determine the total distance traveled and the total time taken for the round trip.
Total Distance: The bus travels a distance of 120 km to the destination and then returns the same distance back. Therefore, the total distance, D = 120km + 120km = 240km
Total Time: To find the total time, we need to calculate the time taken for each leg of the journey separately and then sum these times.
Time to travel to the destination: The bus travels 120 km with a speed of 40 km/h.
t1=Distance/Speed=120 km/40 km/h=3 hours
Time to return: The bus returns the same 120 km distance with a speed of 30 km/h.
t2=DistanceSpeed=120 km30 km/h=4 hours
Therefore, the total time,T for the round trip is:
T=t1+t2=3 hours+4 hours=7 hours
Average Speed: Using the formula for average speed: Average speed=Total distance/Total time=240 km/7 hours
Calculating this gives:
Average speed=240km/7hrs ≈ 34.29 km/h
So, the average speed for the entire journey is approximately 34.29 km/h
Answered on 14 Jun Learn CBSE/Class 10
Hi Riddhi.
I am Adithi. It's disappointing to work very hard for a certain goal and not get the result you deserve. But your 10th grades only show you marks, they cannot indicate your true capabilities.
Keep going, keep learning. Become capable, become technically strong. Then, your marks will just become a byproduct.
Just remember, becoming capable is the goal, not getting marks.
Remember, you will struggle with JEE, regardless of your marks in 10th.
I can help you prepare in a smarter and more efficient manner to help with your stress. I am personally studying at NITK and know exactly what you are going through. Reach out to me anytime. Good luck!
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