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Motion

Motion relates to CBSE/Class 9/Science/Unit 3-Motion, Force and Work

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Answered on 18/04/2024 Learn CBSE/Class 9/Science/Unit 3-Motion, Force and Work/Motion

Nazia Khanum

Solution: Given Data: Initial velocity, u=54 km/hu=54km/h Final velocity, v=72 km/hv=72km/h Time, t=10 secondst=10seconds Conversion: To perform calculations, we need to convert velocities from km/h to m/s. Conversion: 1 km/h = 13.63.61 m/s Converting Initial Velocity: u=54 km/h×13.6=15 m/su=54km/h×3.61=15m/s Converting... read more

Solution:

Given Data:

  • Initial velocity, u=54 km/hu=54km/h
  • Final velocity, v=72 km/hv=72km/h
  • Time, t=10 secondst=10seconds

Conversion: To perform calculations, we need to convert velocities from km/h to m/s.

Conversion: 1 km/h = 13.63.61 m/s

Converting Initial Velocity: u=54 km/h×13.6=15 m/su=54km/h×3.61=15m/s

Converting Final Velocity: v=72 km/h×13.6=20 m/sv=72km/h×3.61=20m/s

(i) Acceleration (aa):

Formula: a=v−uta=tv−u

Substituting Values: a=20 m/s−15 m/s10 sa=10s20m/s−15m/s

Calculation: a=5 m/s10 s=0.5 m/s2a=10s5m/s=0.5m/s2

(ii) Distance Covered (ss):

Formula: s=ut+12at2s=ut+21at2

Substituting Values: s=(15 m/s×10 s)+12×0.5 m/s2×(10 s)2s=(15m/s×10s)+21×0.5m/s2×(10s)2

Calculation: s=(150 m)+0.5×5×100=150+250=400 ms=(150m)+0.5×5×100=150+250=400m

Answer: (i) Acceleration a=0.5 m/s2a=0.5m/s2 (ii) Distance Covered s=400 ms=400m

Therefore, the bus accelerates at 0.5 m/s20.5m/s2 and covers a distance of 400 m400m during this interval.

 
 
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Answered on 18/04/2024 Learn CBSE/Class 9/Science/Unit 3-Motion, Force and Work/Motion

Nazia Khanum

Given Information: Speed of the car: First half hour: 30 km/h Second hour: 25 km/h Third hour: 40 km/h Step 1: Calculate the total distance traveled Distance covered in the first half hour: 30 km/h×0.5 h=15 km30km/h×0.5h=15km Distance covered in the second hour:... read more

Given Information:

  • Speed of the car:
    • First half hour: 30 km/h
    • Second hour: 25 km/h
    • Third hour: 40 km/h

Step 1: Calculate the total distance traveled

  • Distance covered in the first half hour: 30 km/h×0.5 h=15 km30km/h×0.5h=15km
  • Distance covered in the second hour: 25 km/h×1 h=25 km25km/h×1h=25km
  • Distance covered in the third hour: 40 km/h×2 h=80 km40km/h×2h=80km

Total distance = 15 km+25 km+80 km=120 km15km+25km+80km=120km

Step 2: Calculate the total time taken

Total time taken = 0.5 h+1 h+2 h=3.5 h0.5h+1h+2h=3.5h

Step 3: Calculate the average speed

Average speed = Total distance / Total time taken

Average speed = 120 km/3.5 h=34.29 km/h120km/3.5h=34.29km/h

Step 4: Final Answer

Therefore, the average speed of the car is 34.29 km/h34.29km/h.

 
 
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