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Rohini S. Class 9 Tuition trainer in Amroha/>

Rohini S.

Math Teacher

Amroha Bazar, Amroha, India - 244221.

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Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

Rohini S. describes herself as Math Teacher. She conducts classes in Class 10 Tuition and Class 9 Tuition. Rohini is located in Amroha Bazar, Amroha. Rohini takes at students Home and Regular Classes- at her Home. She has 1 years of teaching experience . Rohini has completed Bachelor of Science (B.Sc.) from Rohilkhand university in 2018. She is well versed in English.

Languages Spoken

English

Education

Rohilkhand university 2018

Bachelor of Science (B.Sc.)

Address

Amroha Bazar, Amroha, India - 244221

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Teaches

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

1

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

Yes

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

1

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

Yes

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 10 do you teach for?

CBSE

2. Do you have any prior teaching experience?

Yes

3. Which classes do you teach?

I teach Class 10 Tuition and Class 9 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 1 year.

Answers by Rohini S. (2)

Answered on 31/03/2018 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

Let marks of maths be x And marks of science be y According to question X + Y =28.....(1) (X+3)(Y-4)=180......(2) (X+3)(28-X-4)=180.....(putting value of y from equation 1) (X+3)(24-x)=180 Solving the equation we will get X=12,9 Using equation 1 Y=16,19respectively ...more

Let marks of maths be x

And marks of science be y

According to question

X + Y =28.....(1)

(X+3)(Y-4)=180......(2)

(X+3)(28-X-4)=180.....(putting value of y from equation 1)

(X+3)(24-x)=180

Solving the equation we will get

X=12,9

Using equation 1

Y=16,19respectively

 

Answers 7 Comments
Dislike Bookmark

Answered on 31/03/2018 Learn CBSE/Class 10/Mathematics +2 Tuition/Class IX-X Tuition Profit, Loss and Discount

Costprice =1400 15% of 1400=210 Selling price=cost price -loss =1400 -210 =1190
Answers 39 Comments
Dislike Bookmark

Teaches

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

1

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

Yes

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

1

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

Yes

No Reviews yet!

Answers by Rohini S. (2)

Answered on 31/03/2018 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

Let marks of maths be x And marks of science be y According to question X + Y =28.....(1) (X+3)(Y-4)=180......(2) (X+3)(28-X-4)=180.....(putting value of y from equation 1) (X+3)(24-x)=180 Solving the equation we will get X=12,9 Using equation 1 Y=16,19respectively ...more

Let marks of maths be x

And marks of science be y

According to question

X + Y =28.....(1)

(X+3)(Y-4)=180......(2)

(X+3)(28-X-4)=180.....(putting value of y from equation 1)

(X+3)(24-x)=180

Solving the equation we will get

X=12,9

Using equation 1

Y=16,19respectively

 

Answers 7 Comments
Dislike Bookmark

Answered on 31/03/2018 Learn CBSE/Class 10/Mathematics +2 Tuition/Class IX-X Tuition Profit, Loss and Discount

Costprice =1400 15% of 1400=210 Selling price=cost price -loss =1400 -210 =1190
Answers 39 Comments
Dislike Bookmark

Rohini S. describes herself as Math Teacher. She conducts classes in Class 10 Tuition and Class 9 Tuition. Rohini is located in Amroha Bazar, Amroha. Rohini takes at students Home and Regular Classes- at her Home. She has 1 years of teaching experience . Rohini has completed Bachelor of Science (B.Sc.) from Rohilkhand university in 2018. She is well versed in English.

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