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In a class test, the sum of marks obtained by P in Mathematics and Science is 28. Had he got 3 more marks in Mathematics and 4 marks less in Science, the product of marks obtained in the two subjects would have been 180? Find the marks obtained in two subjects separately.

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Let the marks of mathematics be x Than marks of science be 28-x now according to question (x+3), (28-x-4) The product of new marks will be 180 So, (x+3) (28-x-4)=180 24x-x^2+72-3x=180 x^2-21x+108=0 x^2-12x-9x+108=0 x(x-12)-9(x-12)=0 (x-9)(x-12)=0 (x-9)=0 than x=9 (x-12)=0than x=12 If 9 marks got...
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Let the marks of mathematics be x 

Than marks of science be 28-x 

now according to question 

(x+3), 

(28-x-4)

The product of new marks will be 180

So, 

(x+3) (28-x-4)=180

24x-x^2+72-3x=180

x^2-21x+108=0

x^2-12x-9x+108=0

x(x-12)-9(x-12)=0

(x-9)(x-12)=0

(x-9)=0 than x=9

(x-12)=0than x=12

If 9 marks got in math than 19 marks got in science

If 12 marks got in math than 16 marks got in science 

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Tutor

Let the marks of mathematics and science be x and 28-x respectively.Given :-Mathematics: x+3Science: 28-x-4= 24-x.: Their product=( x+3)(24-x)=24x-x^2+72-3x= 21x-x^2+72But given product= 180=> 21x-x^2+72=180=>x^2-21x-72+180=0=>x^2-21x+108=0=>x^2-12x-9x+108=0=>x(x-12)-9(x-12)=0=>(x-9)(x-12)=...
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Let the marks of mathematics and science be x and 28-x respectively.
Given :-
Mathematics: x+3
Science: 28-x-4= 24-x
.: Their product=( x+3)(24-x)
=24x-x^2+72-3x
= 21x-x^2+72
But given product= 180
=> 21x-x^2+72=180
=>x^2-21x-72+180=0
=>x^2-21x+108=0
=>x^2-12x-9x+108=0
=>x(x-12)-9(x-12)=0
=>(x-9)(x-12)= 0
.: x= 9 or 12
When x= 9
Marks are 9 and 19
When x= 12
Marks are 12 and 16.

 

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Teacher

Let the marks of mathematics be x Then marks of science be 28-x , now according to question (x+3), (28-x-4) The product of new marks will be 180 So, (x+3) (28-x-4)=180, 24x-x^2+72-3x=180 x^2-21x+108=0 x^2-12x-9x+108=0 x(x-12)-9(x-12)=0 (x-9)(x-12)=0 (x-9)=0 than x=9 (x-12)=0than x=12 If 9 marks got...
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Let the marks of mathematics be x 

Then marks of science be 28-x ,

now according to question 

(x+3), 

(28-x-4)

The product of new marks will be 180

So, 

(x+3) (28-x-4)=180,

24x-x^2+72-3x=180

x^2-21x+108=0

x^2-12x-9x+108=0

x(x-12)-9(x-12)=0

(x-9)(x-12)=0

(x-9)=0 than x=9

(x-12)=0than x=12

If 9 marks got in math than 19 marks got in science

If 12 marks got in math than 16 marks got in science

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Math Teacher

Let marks of maths be x And marks of science be y According to question X + Y =28.....(1) (X+3)(Y-4)=180......(2) (X+3)(28-X-4)=180.....(putting value of y from equation 1) (X+3)(24-x)=180 Solving the equation we will get X=12,9 Using equation 1 Y=16,19respectively
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Let marks of maths be x

And marks of science be y

According to question

X + Y =28.....(1)

(X+3)(Y-4)=180......(2)

(X+3)(28-X-4)=180.....(putting value of y from equation 1)

(X+3)(24-x)=180

Solving the equation we will get

X=12,9

Using equation 1

Y=16,19respectively

 

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Primary Teacher

Let the marks of mathematics and science be x and 28-x respectively.Given :-Mathematics: x+3Science: 28-x-4= 24-x.: Their product=( x+3)(24-x)=24x-x^2+72-3x= 21x-x^2+72But given product= 180=> 21x-x^2+72=180=>x^2-21x-72+180=0=>x^2-21x+108=0=>x^2-12x-9x+108=0=>x(x-12)-9(x-12)=0=>(x-9)(x-12)=...
read more

Let the marks of mathematics and science be x and 28-x respectively.
Given :-
Mathematics: x+3
Science: 28-x-4= 24-x
.: Their product=( x+3)(24-x)
=24x-x^2+72-3x
= 21x-x^2+72
But given product= 180
=> 21x-x^2+72=180
=>x^2-21x-72+180=0
=>x^2-21x+108=0
=>x^2-12x-9x+108=0
=>x(x-12)-9(x-12)=0
=>(x-9)(x-12)= 0
.: x= 9 or 12
When x= 9
Marks are 9 and 19
When x= 12
Marks are 12 and 16.

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Math Magician

P got (X) mark in math , (28 – X) mark in science , So (X+3)((28 – X – 4) =180 .OR (X +3)( 24 – X) =180 . OR 21X – X^2 +72 = 180, OR 180 – 72 – 21X + X^2 = 0 OR 108 – 21X + X^2 = 0 . OR (X -12)(X – 9) =0 . P got...
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P    got      (X) mark in math ,    (28 – X)  mark in science ,  So  (X+3)((28 – X – 4)  =180  .OR  (X +3)( 24 – X) =180 .  OR  21X – X^2 +72 = 180, OR  180 – 72 – 21X + X^2  = 0  OR   108 – 21X + X^2 = 0 .     OR  (X -12)(X – 9)  =0  .

   P   got mark(  MATH  =9 ,science =19)  OR (MATH= 12,Science = 16) ANSWER  .

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Comments

m >>>> Marks in maths. s >>>>> Marks in science m+s= 28 >>>>> m=28-s (m+3)(s-4)=180 (31-s)(s-4)=180 -s^2+35s-124=180 s^2-35s+304=0 (s-16)(s-19)=0 s=16, 19 When s=16, m=12 When s=19, m=9 Hence the possible marks in subject maths and science are respectively (9,...
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m >>>> Marks in maths.

s >>>>> Marks in science

m+s= 28 >>>>> m=28-s

(m+3)(s-4)=180

(31-s)(s-4)=180

-s^2+35s-124=180

s^2-35s+304=0

(s-16)(s-19)=0

s=16, 19

When s=16, m=12

When s=19, m=9

Hence the possible marks in subject maths and science are respectively (9, 19); (12, 16).

 

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