Subhas Pally, Siliguri, India - 734001
Verified 7
Details verified of Bikash C.✕
Identity
Education
Know how UrbanPro verifies Tutor details
Identity is verified based on matching the details uploaded by the Tutor with government databases.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
2
Board
CBSE
CBSE Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
2
Board
CBSE
CBSE Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
2
Board
CBSE
CBSE Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
2
Board
CBSE
CBSE Subjects taught
Mathematics
Taught in School or College
No
5 out of 5 4 reviews
Shreyash Mayank
Class 10 Tuition
"Really great, loving and excellent teaching style and nature. I would recommend to all. "
Hritik Dubey
"Sir is very intelligent and he knows well that how to draw attention of students towards study (this sir is super and God for me) "
Piyush Baibhav
Class 11 Tuition
"My experience is very good. He is very good teacher. He explain anything in very easy and simple way. He can explain anything and work very hard for their students. "
Jayesh Mishra
"Sir is very intelligent and he(sir) knows well that how to draw the attention of students towards study. "
Answered on 08/09/2019 Learn CBSE/Class 12/Mathematics/Continuity and Differentiability/NCERT Solutions/Exercise 5.5
First differentiate first term and then second term . Consider y1=x to the power sin x then
Log Y1 equal to to log within bracket x to the power sin Differentiate both sides.
Considered Y2equal to sin x to the power cosx and then log Y2 2 equal to tu log sin x to the power cosx and then differentiate both side now add this to differentiate and that is your answer.
Answered on 08/09/2019 Learn Tuition
Answered on 04/09/2019 Learn CBSE/Class 12/Mathematics/Continuity and Differentiability/NCERT Solutions/Exercise 5.5
Share this Profile
Reply to 's review
Enter your reply*
Your reply has been successfully submitted.
Certified
The Certified badge indicates that the Tutor has received good amount of positive feedback from Students.