Municipal Council Rd Shikohabad, Shikohabad, India - 283135.
Verified
Details verified of Aman Kumar Gupta✕
Identity
Education
Know how UrbanPro verifies Tutor details
Identity is verified based on matching the details uploaded by the Tutor with government databases.
Hindi Mother Tongue (Native)
English Basic
IGNOU 2014
Bachelor of Technology (B.Tech.)
Municipal Council Rd Shikohabad, Shikohabad, India - 283135
ID Verified
Education Verified
Phone Verified
Email Verified
Report this Profile
Is this listing inaccurate or duplicate? Any other problem?
Please tell us about the problem and we will fix it.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
2
Board
CBSE
CBSE Subjects taught
Science, Mathematics
Experience in School or College
I enjoy so i love teaching. I always give my best and try to use different-2 ways to make students to understand the concept instead of learning. I taught 1 year but my experience was too good. And students was happy with me.
Taught in School or College
Yes
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
2
Board
CBSE
CBSE Subjects taught
Science, Mathematics
Experience in School or College
Teaching is my passion. I taught in different-2 ways just to make students understood the concepts. Students were satisfied with my way of teaching and this was a great experience.
Taught in School or College
Yes
Teaching Experience in detail in Class 9 Tuition
I teach in very well manner with lots of examples in different-2 ways on several topics that opens the mind of students and s/he becomes to think more about concepts. I always try to make understand in simple ways thus students can remember the topic. In this manner i enjoy when i teach as i did in the past. Students make me feel special and that is a great experience for me.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
2
Board
CBSE
CBSE Subjects taught
Science, Mathematics
Taught in School or College
No
1. Which school boards of Class 10 do you teach for?
CBSE
2. Do you have any prior teaching experience?
Yes
3. Which classes do you teach?
I teach Class 10 Tuition, Class 8 Tuition and Class 9 Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 2 years.
Answered on 09/08/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.3
Let Rehman's present age be x
So before 3 years age=(x-3) years
His age after 5 years= (x+5) years
So a/c to given data
x(x-7)+3(x-7)=0
(x-7)(x+3)=0
So, x=7 or -3
Age can not be negative soRehman's present age is 7 years.
Answered on 09/08/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.3
1) x^2-1=3x
x^2-3x-1=0
Apply quadratic formula i.e. {-b±√(b^2-4ac)}/2a
So, roots= {3±√(9+4)}/2 = {3±√13}/2
So roots are {3+√13}/2 and {3-√13}/2 i.e. and
2) (x-7-x-4)×30 =11×(x+4)(x-7)
-330=11×(x^2-3x-28)
x^2-3x-28+30=0
X^2-3x+2=0
X^2-2x-x+2=0
x(x-2)-1(x-2)=0
(x-2)(x-1)=0
x=1,2 i.e. ans
Answered on 09/08/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Arithmetic Progression/NCERT Solutions/Exercise 5.3
Length of semicircle=circumference/2 = 2Πr/2=Πr
There are 13 semicircles with radius
0.5,1,1.5,2,2.5,3,3.5,4,4.5,5,5.5,6,6.5
I.e. in AP whose 1St term=0.5 &
common difference=0.5
Now, total length of spiral=Π(0.5+1+1.5+2+2.5+3+3.5+4+4.5+5+5.5+6+6.5)
As we know sum of an AP is=
no. of terms(1St term+last term)/2= 13(0.5+6.5)/2=13×7/2=91/2
Now put value
Total length of spiral =(22/7)×(91/2)=11×13=143cm i.e. ans
Answered on 07/08/2019 Learn Tuition
To verify the solution of the question.just put either value of x or y then you all get another's value i.e. y or x or put value of both x and y in the equation you will get the LHS=RHS.
Put x=1
2×1-3y=8
2-3y=8
2-8=3y
y=(-6/3)
y=-2 i.e. given so verified.
Similarly when you put y=-2 you all get x=1.
Now, put both x=1 & y=-2
2×1-3×(-2)=8
2+6=8
8=8
LHS=RHS so verified.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
2
Board
CBSE
CBSE Subjects taught
Science, Mathematics
Experience in School or College
I enjoy so i love teaching. I always give my best and try to use different-2 ways to make students to understand the concept instead of learning. I taught 1 year but my experience was too good. And students was happy with me.
Taught in School or College
Yes
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
2
Board
CBSE
CBSE Subjects taught
Science, Mathematics
Experience in School or College
Teaching is my passion. I taught in different-2 ways just to make students understood the concepts. Students were satisfied with my way of teaching and this was a great experience.
Taught in School or College
Yes
Teaching Experience in detail in Class 9 Tuition
I teach in very well manner with lots of examples in different-2 ways on several topics that opens the mind of students and s/he becomes to think more about concepts. I always try to make understand in simple ways thus students can remember the topic. In this manner i enjoy when i teach as i did in the past. Students make me feel special and that is a great experience for me.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
2
Board
CBSE
CBSE Subjects taught
Science, Mathematics
Taught in School or College
No
Answered on 09/08/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.3
Let Rehman's present age be x
So before 3 years age=(x-3) years
His age after 5 years= (x+5) years
So a/c to given data
x(x-7)+3(x-7)=0
(x-7)(x+3)=0
So, x=7 or -3
Age can not be negative soRehman's present age is 7 years.
Answered on 09/08/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.3
1) x^2-1=3x
x^2-3x-1=0
Apply quadratic formula i.e. {-b±√(b^2-4ac)}/2a
So, roots= {3±√(9+4)}/2 = {3±√13}/2
So roots are {3+√13}/2 and {3-√13}/2 i.e. and
2) (x-7-x-4)×30 =11×(x+4)(x-7)
-330=11×(x^2-3x-28)
x^2-3x-28+30=0
X^2-3x+2=0
X^2-2x-x+2=0
x(x-2)-1(x-2)=0
(x-2)(x-1)=0
x=1,2 i.e. ans
Answered on 09/08/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Arithmetic Progression/NCERT Solutions/Exercise 5.3
Length of semicircle=circumference/2 = 2Πr/2=Πr
There are 13 semicircles with radius
0.5,1,1.5,2,2.5,3,3.5,4,4.5,5,5.5,6,6.5
I.e. in AP whose 1St term=0.5 &
common difference=0.5
Now, total length of spiral=Π(0.5+1+1.5+2+2.5+3+3.5+4+4.5+5+5.5+6+6.5)
As we know sum of an AP is=
no. of terms(1St term+last term)/2= 13(0.5+6.5)/2=13×7/2=91/2
Now put value
Total length of spiral =(22/7)×(91/2)=11×13=143cm i.e. ans
Answered on 07/08/2019 Learn Tuition
To verify the solution of the question.just put either value of x or y then you all get another's value i.e. y or x or put value of both x and y in the equation you will get the LHS=RHS.
Put x=1
2×1-3y=8
2-3y=8
2-8=3y
y=(-6/3)
y=-2 i.e. given so verified.
Similarly when you put y=-2 you all get x=1.
Now, put both x=1 & y=-2
2×1-3×(-2)=8
2+6=8
8=8
LHS=RHS so verified.
Share this Profile
Reply to 's review
Enter your reply*
Your reply has been successfully submitted.
Certified
The Certified badge indicates that the Tutor has received good amount of positive feedback from Students.