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Overview

I am a to be 'Electronics & Instrumentation Engineer' currently in my final semester. I have been tutoring since 2014 giving both home/online tuition. Teaching is my passion. My domain of excellence is Mathematics. My focus is to grow the interest of the beautiful subject among the students and also breaking down difficult concepts which are hard to understand. Do reach out by contacting me anytime if you face any doubts or difficulties. Looking forward to work with you and do some wonders together.

Languages Spoken

Bengali Mother Tongue (Native)

Hindi Proficient

English Proficient

Education

Maulana Abul Kalam Azad University of Technology Pursuing

Bachelor of Technology (B.Tech.)

Address

Tollygunge, Kolkata, India - 700095

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Teaches

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

6

NIOS Subjects taught

Mathematics

Board

International Baccalaureate, ICSE, State, NIOS, IGCSE, CBSE

IB Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

IGCSE Subjects taught

Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

6

NIOS Subjects taught

Mathematics

Board

International Baccalaureate, ICSE, State, NIOS, IGCSE, CBSE

IB Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

IGCSE Subjects taught

Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

6

NIOS Subjects taught

Mathematics

Board

ICSE, State, CBSE, International Baccalaureate, NIOS, IGCSE

IB Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

IGCSE Subjects taught

Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

6

NIOS Subjects taught

Mathematics

Board

ICSE, State, CBSE, International Baccalaureate, NIOS, IGCSE

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

IGCSE Subjects taught

Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 10 do you teach for?

International Baccalaureate, ICSE, State and others

2. Do you have any prior teaching experience?

No

3. Which classes do you teach?

I teach Class 10 Tuition, Class 7 Tuition, Class 8 Tuition and Class 9 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a paid demo class.

5. How many years of experience do you have?

I have been teaching for 6 years.

Answers by Subham Chakravarti (3)

Answered on 09/06/2020 Learn Tuition

Hello Abhishree, Being an Engineering student currently in my final year and also a part-time Mathematics tutor, I think that I can answer this question. During the prevailing conditions outside, you, being a student, should be having mixed feelings staying indoors. The only reference to your studies... ...more

Hello Abhishree,

Being an Engineering student currently in my final year and also a part-time Mathematics tutor, I think that I can answer this question.

During the prevailing conditions outside, you, being a student, should be having mixed feelings staying indoors. The only reference to your studies are books, the Internet - Google, Youtube, etc. But some subjects need better understanding which goes much beyond mere videos and books, for example, Mathematics, which involves doubt clearing and concept boosting thus making the layers of your foundation stronger.

With the technology being so advanced nowadays and video calling applications like Zoom, Cisco Webex, Skype, Google Meet, etc. and the options of sharing the screen, I think that it is innovative and advisable for the online tuitions . It is no different from offline teachings. The only difference being you are seeing your mentor virtually. This method of flowing of knowledge and education makes studying more enjoyable.

Good luck and happy learning.

All the Best! 

Answers 2388 Comments
Dislike Bookmark

Answered on 02/06/2020 Learn Tuition

5(x2 + y2 + z2) = 4(xy + yz + zx) or, 5x2 + 5y2 + 5z2 = 4xy + 4yz + 4zx or, 4x2 + 4y2 + 4z2 + x2 + y2 + z2 = 4xy + 4yz + 4zx or, (4x2 – 4xy + y2) + (4y2 – 4yz + z2) + (4z2 – 4zx + x2) = 0 or, (2x - y)2 + (2y - z)2 + (2z - x)2 = 0 We know that, since sum of squares is 0, each square... ...more

5(x2 + y2 + z2) = 4(xy + yz + zx)

or, 5x2 + 5y2 + 5z2 = 4xy + 4yz + 4zx

or, 4x2 + 4y2 + 4z2 + x2 + y2 + z2 = 4xy + 4yz + 4zx

or, (4x2 – 4xy + y2) + (4y2 – 4yz + z2) + (4z2 – 4zx + x2) = 0

or, (2x - y)2 + (2y - z)2 + (2z - x)2 = 0

We know that, since sum of squares is 0, each square must be equal to 0.

Therefore,
                   (2x - y)2 = (2y - z)2 = (2z - x)2 = 0

             or, (2x - y) = (2y - z) = (2z - x) = 0

Therefore,

                       2x = y, 2y = z, 2z = x.

Thus converting all terms in respect to ‘x’ we get,
                                           y = 2x
                                           z = x/2
Therefore,
                   x : y : z = x : 2x : x/2
                                = 1 : 2 : ½
                                = 2 : 4 : 1

Answer:      x : y : z = 2 : 4 : 1

Answers 353 Comments
Dislike Bookmark

Answered on 02/06/2020 Learn Tuition

5(x2 + y2 + z2) = 4(xy + yz + zx) or, 5x2 + 5y2 + 5z2 = 4xy + 4yz + 4zx or, 4x2 + 4y2 + 4z2 + x2 + y2 + z2 = 4xy + 4yz + 4zx or, (4x2 – 4xy + y2) + (4y2 – 4yz + z2) + (4z2 – 4zx + x2) = 0 or, (2x - y)2 + (2y - z)2 + (2z - x)2 = 0 We know that, since sum of squares is 0, each square... ...more

5(x2 + y2 + z2) = 4(xy + yz + zx)

or, 5x2 + 5y2 + 5z2 = 4xy + 4yz + 4zx

or, 4x2 + 4y2 + 4z2 + x2 + y2 + z2 = 4xy + 4yz + 4zx

or, (4x2 – 4xy + y2) + (4y2 – 4yz + z2) + (4z2 – 4zx + x2) = 0

or, (2x - y)2 + (2y - z)2 + (2z - x)2 = 0

We know that, since sum of squares is 0, each square must be equal to 0.

Therefore,
                   (2x - y)2 = (2y - z)2 = (2z - x)2 = 0

             or, (2x - y) = (2y - z) = (2z - x) = 0

Therefore,

                       2x = y, 2y = z, 2z = x.

Thus converting all terms in respect to ‘x’ we get,
                                           y = 2x
                                           z = x/2
Therefore,
                   x : y : z = x : 2x : x/2
                                = 1 : 2 : ½
                                = 2 : 4 : 1

Answer:      x : y : z = 2 : 4 : 1

Answers 353 Comments
Dislike Bookmark

Teaches

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

6

NIOS Subjects taught

Mathematics

Board

International Baccalaureate, ICSE, State, NIOS, IGCSE, CBSE

IB Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

IGCSE Subjects taught

Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

6

NIOS Subjects taught

Mathematics

Board

International Baccalaureate, ICSE, State, NIOS, IGCSE, CBSE

IB Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

IGCSE Subjects taught

Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

6

NIOS Subjects taught

Mathematics

Board

ICSE, State, CBSE, International Baccalaureate, NIOS, IGCSE

IB Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

IGCSE Subjects taught

Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

6

NIOS Subjects taught

Mathematics

Board

ICSE, State, CBSE, International Baccalaureate, NIOS, IGCSE

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

IGCSE Subjects taught

Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

No Reviews yet!

Answers by Subham Chakravarti (3)

Answered on 09/06/2020 Learn Tuition

Hello Abhishree, Being an Engineering student currently in my final year and also a part-time Mathematics tutor, I think that I can answer this question. During the prevailing conditions outside, you, being a student, should be having mixed feelings staying indoors. The only reference to your studies... ...more

Hello Abhishree,

Being an Engineering student currently in my final year and also a part-time Mathematics tutor, I think that I can answer this question.

During the prevailing conditions outside, you, being a student, should be having mixed feelings staying indoors. The only reference to your studies are books, the Internet - Google, Youtube, etc. But some subjects need better understanding which goes much beyond mere videos and books, for example, Mathematics, which involves doubt clearing and concept boosting thus making the layers of your foundation stronger.

With the technology being so advanced nowadays and video calling applications like Zoom, Cisco Webex, Skype, Google Meet, etc. and the options of sharing the screen, I think that it is innovative and advisable for the online tuitions . It is no different from offline teachings. The only difference being you are seeing your mentor virtually. This method of flowing of knowledge and education makes studying more enjoyable.

Good luck and happy learning.

All the Best! 

Answers 2388 Comments
Dislike Bookmark

Answered on 02/06/2020 Learn Tuition

5(x2 + y2 + z2) = 4(xy + yz + zx) or, 5x2 + 5y2 + 5z2 = 4xy + 4yz + 4zx or, 4x2 + 4y2 + 4z2 + x2 + y2 + z2 = 4xy + 4yz + 4zx or, (4x2 – 4xy + y2) + (4y2 – 4yz + z2) + (4z2 – 4zx + x2) = 0 or, (2x - y)2 + (2y - z)2 + (2z - x)2 = 0 We know that, since sum of squares is 0, each square... ...more

5(x2 + y2 + z2) = 4(xy + yz + zx)

or, 5x2 + 5y2 + 5z2 = 4xy + 4yz + 4zx

or, 4x2 + 4y2 + 4z2 + x2 + y2 + z2 = 4xy + 4yz + 4zx

or, (4x2 – 4xy + y2) + (4y2 – 4yz + z2) + (4z2 – 4zx + x2) = 0

or, (2x - y)2 + (2y - z)2 + (2z - x)2 = 0

We know that, since sum of squares is 0, each square must be equal to 0.

Therefore,
                   (2x - y)2 = (2y - z)2 = (2z - x)2 = 0

             or, (2x - y) = (2y - z) = (2z - x) = 0

Therefore,

                       2x = y, 2y = z, 2z = x.

Thus converting all terms in respect to ‘x’ we get,
                                           y = 2x
                                           z = x/2
Therefore,
                   x : y : z = x : 2x : x/2
                                = 1 : 2 : ½
                                = 2 : 4 : 1

Answer:      x : y : z = 2 : 4 : 1

Answers 353 Comments
Dislike Bookmark

Answered on 02/06/2020 Learn Tuition

5(x2 + y2 + z2) = 4(xy + yz + zx) or, 5x2 + 5y2 + 5z2 = 4xy + 4yz + 4zx or, 4x2 + 4y2 + 4z2 + x2 + y2 + z2 = 4xy + 4yz + 4zx or, (4x2 – 4xy + y2) + (4y2 – 4yz + z2) + (4z2 – 4zx + x2) = 0 or, (2x - y)2 + (2y - z)2 + (2z - x)2 = 0 We know that, since sum of squares is 0, each square... ...more

5(x2 + y2 + z2) = 4(xy + yz + zx)

or, 5x2 + 5y2 + 5z2 = 4xy + 4yz + 4zx

or, 4x2 + 4y2 + 4z2 + x2 + y2 + z2 = 4xy + 4yz + 4zx

or, (4x2 – 4xy + y2) + (4y2 – 4yz + z2) + (4z2 – 4zx + x2) = 0

or, (2x - y)2 + (2y - z)2 + (2z - x)2 = 0

We know that, since sum of squares is 0, each square must be equal to 0.

Therefore,
                   (2x - y)2 = (2y - z)2 = (2z - x)2 = 0

             or, (2x - y) = (2y - z) = (2z - x) = 0

Therefore,

                       2x = y, 2y = z, 2z = x.

Thus converting all terms in respect to ‘x’ we get,
                                           y = 2x
                                           z = x/2
Therefore,
                   x : y : z = x : 2x : x/2
                                = 1 : 2 : ½
                                = 2 : 4 : 1

Answer:      x : y : z = 2 : 4 : 1

Answers 353 Comments
Dislike Bookmark

Subham Chakravarti describes himself as Tutor with an experience in teaching Mathematics since 6 years.. He conducts classes in Class 10 Tuition, Class 7 Tuition and Class 8 Tuition. Subham is located in Tollygunge, Kolkata. Subham takes at students Home, Regular Classes- at his Home and Online Classes- via online medium. He has 6 years of teaching experience . Subham is pursuing Bachelor of Technology (B.Tech.) from Maulana Abul Kalam Azad University of Technology. HeĀ is well versed in Bengali, Hindi and English.

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