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Overview

Rishiraj K. describes himself as B.tech. He conducts classes in Class 10 Tuition and Class 9 Tuition. Rishiraj is located in Debhog, Haldia. Rishiraj takes at students Home, Regular Classes- at his Home and Online Classes- via online medium. Rishiraj is pursuing Bachelor of Technology (B.Tech.) from Haldia institute of technology. He is well versed in English.

Languages Spoken

English Proficient

Education

Haldia institute of technology Pursuing

Bachelor of Technology (B.Tech.)

Address

Debhog, Haldia, India - 721657

Verified Info

Phone Verified

Email Verified

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Teaches

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, State, ICSE, IGCSE

CBSE Subjects taught

Science, Mathematics, Hindi

ICSE Subjects taught

Hindi, Chemistry, Mathematics, Physics

IGCSE Subjects taught

Physics, Mathematics, Hindi, Chemistry

Taught in School or College

No

State Syllabus Subjects taught

Hindi, Science, Mathematics

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, State, ICSE, IGCSE

CBSE Subjects taught

Science, Mathematics, Hindi

ICSE Subjects taught

Hindi, Chemistry, Mathematics, Physics

IGCSE Subjects taught

Physics, Mathematics, Hindi, Chemistry

Taught in School or College

No

State Syllabus Subjects taught

Hindi, Science, Mathematics

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 10 do you teach for?

CBSE, State, ICSE and others

2. Do you have any prior teaching experience?

No

3. Which classes do you teach?

I teach Class 10 Tuition and Class 9 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for less than a year.

Answers by Rishiraj K. (3)

Answered on 24/11/2017 Learn Tuition/Class IX-X Tuition

Basically Newton second law of motion state that the rate of change of momentum is directly proportional to the net force applied on the body
Answers 206 Comments
Dislike Bookmark

Answered on 24/11/2017 Learn Tuition/Class IX-X Tuition

Putting the respective value of the given trigonometric ratios We get a indeterminate form 1/0 whose value is not defined
Answers 206 Comments
Dislike Bookmark

Answered on 24/11/2017 Learn Tuition/Class IX-X Tuition

Basically the second law of motion says that Rate of change in momentum of a body is equal to the net force applied on the body.
Answers 206 Comments
Dislike Bookmark

Teaches

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, State, ICSE, IGCSE

CBSE Subjects taught

Science, Mathematics, Hindi

ICSE Subjects taught

Hindi, Chemistry, Mathematics, Physics

IGCSE Subjects taught

Physics, Mathematics, Hindi, Chemistry

Taught in School or College

No

State Syllabus Subjects taught

Hindi, Science, Mathematics

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, State, ICSE, IGCSE

CBSE Subjects taught

Science, Mathematics, Hindi

ICSE Subjects taught

Hindi, Chemistry, Mathematics, Physics

IGCSE Subjects taught

Physics, Mathematics, Hindi, Chemistry

Taught in School or College

No

State Syllabus Subjects taught

Hindi, Science, Mathematics

No Reviews yet!

Answers by Rishiraj K. (3)

Answered on 24/11/2017 Learn Tuition/Class IX-X Tuition

Basically Newton second law of motion state that the rate of change of momentum is directly proportional to the net force applied on the body
Answers 206 Comments
Dislike Bookmark

Answered on 24/11/2017 Learn Tuition/Class IX-X Tuition

Putting the respective value of the given trigonometric ratios We get a indeterminate form 1/0 whose value is not defined
Answers 206 Comments
Dislike Bookmark

Answered on 24/11/2017 Learn Tuition/Class IX-X Tuition

Basically the second law of motion says that Rate of change in momentum of a body is equal to the net force applied on the body.
Answers 206 Comments
Dislike Bookmark

Rishiraj K. describes himself as B.tech. He conducts classes in Class 10 Tuition and Class 9 Tuition. Rishiraj is located in Debhog, Haldia. Rishiraj takes at students Home, Regular Classes- at his Home and Online Classes- via online medium. Rishiraj is pursuing Bachelor of Technology (B.Tech.) from Haldia institute of technology. He is well versed in English.

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