/> Sector 23 A, Gurgaon, India - 122017.
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Hindi Mother Tongue (Native)
English Proficient
Visveshwarya Technical University 2012
Bachelor of Engineering (B.E.)
Jawaharlal Nehru Technical University 2015
Master of Engineering - Master of Technology (M.E./M.Tech.)
Sector 23 A, Gurgaon, India - 122017
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
2
Board
CBSE
CBSE Subjects taught
Mathematics, Computer Practices, Science
Taught in School or College
Yes
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
2
Board
CBSE
CBSE Subjects taught
Mathematics, Computer Practices, Science
Taught in School or College
Yes
1. Which school boards of Class 10 do you teach for?
CBSE
2. Do you have any prior teaching experience?
Yes
3. Which classes do you teach?
I teach Class 10 Tuition and Class 9 Tuition Classes.
4. Do you provide a demo class?
No, I don't provide a demo class.
5. How many years of experience do you have?
I have been teaching for 2 years.
Answered on 12/05/2020 Learn CBSE/Class 11/Science/Mathematics/Unit-II: Algebra/Complex Numbers and Quadratic Equations/NCERT Solutions/Miscellaneous Exercise 5
As we know Complex Number are defined as
z = x + iy
So, Considering above, we can say the complex numbers z1 and z2 are
z1 = x1 + iy1
z2 = x2 + iy2
According to question, we need to prove,
Re (z1z2) = Re z1 Re z2 – Im z1 Im z2.
Let calculate z1z2, we get,
z1z2 = ( x1 + iy1 ).( x2 + iy2 )
= x1x2 + ix1y2 + ix2y1 + i2y1y2
= x1x2 + ix1y2 + ix2y1 - y1y2 ( :· i2 = -1 )
= x1x2 - y1y2 + ix1y2 + ix2y1 -------> (Eq 1)
Now from we can separate the real part from above Equation, we get
Re (z1z2) = x1x2 - y1y2 -------> (Eq 2)
Now, let take R.H.S, So we have
Re z1 Re z2 – Im z1 Im z2. = x1x2 - y1y2 -------> (Eq 3)
So, Considering Eq (2) and Eq (3), we can prove that
Re (z1z2) = Re z1 Re z2 – Im z1 Im z2.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
2
Board
CBSE
CBSE Subjects taught
Mathematics, Computer Practices, Science
Taught in School or College
Yes
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
2
Board
CBSE
CBSE Subjects taught
Mathematics, Computer Practices, Science
Taught in School or College
Yes
Answered on 12/05/2020 Learn CBSE/Class 11/Science/Mathematics/Unit-II: Algebra/Complex Numbers and Quadratic Equations/NCERT Solutions/Miscellaneous Exercise 5
As we know Complex Number are defined as
z = x + iy
So, Considering above, we can say the complex numbers z1 and z2 are
z1 = x1 + iy1
z2 = x2 + iy2
According to question, we need to prove,
Re (z1z2) = Re z1 Re z2 – Im z1 Im z2.
Let calculate z1z2, we get,
z1z2 = ( x1 + iy1 ).( x2 + iy2 )
= x1x2 + ix1y2 + ix2y1 + i2y1y2
= x1x2 + ix1y2 + ix2y1 - y1y2 ( :· i2 = -1 )
= x1x2 - y1y2 + ix1y2 + ix2y1 -------> (Eq 1)
Now from we can separate the real part from above Equation, we get
Re (z1z2) = x1x2 - y1y2 -------> (Eq 2)
Now, let take R.H.S, So we have
Re z1 Re z2 – Im z1 Im z2. = x1x2 - y1y2 -------> (Eq 3)
So, Considering Eq (2) and Eq (3), we can prove that
Re (z1z2) = Re z1 Re z2 – Im z1 Im z2.
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