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Overview

Bhanwar Lal conducts classes in Class 10 Tuition and Class 9 Tuition. Bhanwar is located in Mehrauli, Delhi. Bhanwar takes at students Home. Bhanwar has completed Bachelor of Technology (B.Tech.) from MNIT JAIPUR in 2017. He is well versed in English and Hindi.

Languages Spoken

English

Hindi

Education

MNIT JAIPUR 2017

Bachelor of Technology (B.Tech.)

Address

Mehrauli, Delhi, India - 110016

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Teaches

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE

CBSE Subjects taught

Science, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Science, Mathematics

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE

CBSE Subjects taught

Science, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Science, Mathematics

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 10 do you teach for?

State, CBSE

2. Do you have any prior teaching experience?

No

3. Which classes do you teach?

I teach Class 10 Tuition and Class 9 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for less than a year.

Contact

Answers by Bhanwar Lal (1)

Answered on 11/01/2018 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

The diameter of a sphere is 28 cm. Find the cost of painting it all around at Rs. 0.10 per square cm.

d=28cm so r=d/2=28/2=14cm Now Area of sphere is, 4πr^2=4*3.14*14^2=2463cm^2 Cost=area*cost of per sq. cm=2463*0.10=Rs 246.3
Answers 8 Comments
Dislike Bookmark

Contact

Teaches

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE

CBSE Subjects taught

Science, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Science, Mathematics

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE

CBSE Subjects taught

Science, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Science, Mathematics

No Reviews yet!

Answers by Bhanwar Lal (1)

Answered on 11/01/2018 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

The diameter of a sphere is 28 cm. Find the cost of painting it all around at Rs. 0.10 per square cm.

d=28cm so r=d/2=28/2=14cm Now Area of sphere is, 4πr^2=4*3.14*14^2=2463cm^2 Cost=area*cost of per sq. cm=2463*0.10=Rs 246.3
Answers 8 Comments
Dislike Bookmark

Contact

Bhanwar Lal conducts classes in Class 10 Tuition and Class 9 Tuition. Bhanwar is located in Mehrauli, Delhi. Bhanwar takes at students Home. Bhanwar has completed Bachelor of Technology (B.Tech.) from MNIT JAIPUR in 2017. He is well versed in English and Hindi.

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