UrbanPro
Login Ask & Answer Success Stories Paid Courses Free Classes Tuition & Classes Fees Write a Review All Categories Help Center
Post your Learning Need Signup as a Tutor
✕

Popular Cities

Bangalore

Hyderabad

Delhi

Mumbai

Chennai

Pune

Kolkata

Gurgaon

Ahmedabad

Jaipur

Noida

✕
true
Aditya Kumar Class 9 Tuition trainer in Delhi

Aditya Kumar

Mathematics

Mukherjee Nagar, Delhi, India - 110009.

Contact
Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

Details verified of Aditya Kumar✕

Identity

Education

Know how UrbanPro verifies Tutor details

Identity is verified based on matching the details uploaded by the Tutor with government databases.

Overview

Initiative and high level of energy.
Tolerant and flexible with different situations.
Verbal communication skills, decision making, critical thinking, organizing and planning.

Languages Spoken

English

Hindi

Education

Sir MVIt 2017

Bachelor of Engineering (B.E.)

Address

Mukherjee Nagar, Delhi, India - 110009

Verified Info

Phone Verified

Email Verified

Report this Profile

✕
x

Is this listing inaccurate or duplicate? Any other problem?

Please tell us about the problem and we will fix it.

Please describe the problem that you see in this page.

Type the letters as shown below *

Please enter the letters as show below

Teaches

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, ICSE, CBSE

CBSE Subjects taught

Science, Mathematics

ICSE Subjects taught

Physics, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, Science

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, ICSE, CBSE

CBSE Subjects taught

Science, Mathematics

ICSE Subjects taught

Physics, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, Science

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

1

Board

State, CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

1

Board

State, CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

1

Board

State, CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 10 do you teach for?

State, ICSE, CBSE

2. Do you have any prior teaching experience?

Yes

3. Which classes do you teach?

I teach Class 10 Tuition, Class 6 Tuition, Class 7 Tuition, Class 8 Tuition and Class 9 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for less than a year.

Contact

Answers by Aditya Kumar (2)

Answered on 16/12/2017 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

If the zeroes of polynomial x3 – ax2 + bx – c are in AP then show that 2a3 – 9ab + 27c = 0

zreors of polynomial means roots of polynomial if the roots of polynomial are in AP then the roots are A+d, A, A-d Sum of the roots = (-) Co-efficient of X^2/ Co-efficient of X^3 = A+d +A +A-d -(-a) = 3A a =3A A= a/3 since... ...more
zreors of polynomial means roots of polynomial if the roots of polynomial are in AP then the roots are A+d, A, A-d Sum of the roots = (-) Co-efficient of X^2/ Co-efficient of X^3 = A+d +A +A-d -(-a) = 3A a =3A A= a/3 since f(x)= x^3 - ax^2 +bx - c f(A)= A^3 - aA^2 +bA -c put A= a/3 (a/3)^3 -a(a/3)^2 +b(a/3) -c=0 (a^3)/27 - (a^3)/9 +ab/3 -c = 0 (a^3) -3(a^3) +9ab -27c =0 -2(a^3) +9ab - 27c = 0 2a^3 -9ab +27c = 0 hence PROVED
Answers 5 Comments
Dislike Bookmark

Answered on 16/12/2017 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

A train, travelling at a uniform speed for 360 km, would have taken 48 minutes less to travel the same... ...more
A train, travelling at a uniform speed for 360 km, would have taken 48 minutes less to travel the same distance if its speed were 5 km/hr more. Find the original speed of the train.

distance=360 km time difference b/w both speed = 48/60 hr let speed of train is x km/hr then time taken by train when speed is x km/hr = 360/x hr time taken by train when speed is x+5 km/hr = 360/(x+5) hr A/C to question 360/x = 360/(x+5) +48/60 after solving this equation you will get the original speed... ...more
distance=360 km time difference b/w both speed = 48/60 hr let speed of train is x km/hr then time taken by train when speed is x km/hr = 360/x hr time taken by train when speed is x+5 km/hr = 360/(x+5) hr A/C to question 360/x = 360/(x+5) +48/60 after solving this equation you will get the original speed of train i.e equal to 45 km/hr
Answers 2 Comments
Dislike Bookmark

Contact

Teaches

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, ICSE, CBSE

CBSE Subjects taught

Science, Mathematics

ICSE Subjects taught

Physics, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, Science

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, ICSE, CBSE

CBSE Subjects taught

Science, Mathematics

ICSE Subjects taught

Physics, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, Science

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

1

Board

State, CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

1

Board

State, CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

1

Board

State, CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics

No Reviews yet!

Answers by Aditya Kumar (2)

Answered on 16/12/2017 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

If the zeroes of polynomial x3 – ax2 + bx – c are in AP then show that 2a3 – 9ab + 27c = 0

zreors of polynomial means roots of polynomial if the roots of polynomial are in AP then the roots are A+d, A, A-d Sum of the roots = (-) Co-efficient of X^2/ Co-efficient of X^3 = A+d +A +A-d -(-a) = 3A a =3A A= a/3 since... ...more
zreors of polynomial means roots of polynomial if the roots of polynomial are in AP then the roots are A+d, A, A-d Sum of the roots = (-) Co-efficient of X^2/ Co-efficient of X^3 = A+d +A +A-d -(-a) = 3A a =3A A= a/3 since f(x)= x^3 - ax^2 +bx - c f(A)= A^3 - aA^2 +bA -c put A= a/3 (a/3)^3 -a(a/3)^2 +b(a/3) -c=0 (a^3)/27 - (a^3)/9 +ab/3 -c = 0 (a^3) -3(a^3) +9ab -27c =0 -2(a^3) +9ab - 27c = 0 2a^3 -9ab +27c = 0 hence PROVED
Answers 5 Comments
Dislike Bookmark

Answered on 16/12/2017 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

A train, travelling at a uniform speed for 360 km, would have taken 48 minutes less to travel the same... ...more
A train, travelling at a uniform speed for 360 km, would have taken 48 minutes less to travel the same distance if its speed were 5 km/hr more. Find the original speed of the train.

distance=360 km time difference b/w both speed = 48/60 hr let speed of train is x km/hr then time taken by train when speed is x km/hr = 360/x hr time taken by train when speed is x+5 km/hr = 360/(x+5) hr A/C to question 360/x = 360/(x+5) +48/60 after solving this equation you will get the original speed... ...more
distance=360 km time difference b/w both speed = 48/60 hr let speed of train is x km/hr then time taken by train when speed is x km/hr = 360/x hr time taken by train when speed is x+5 km/hr = 360/(x+5) hr A/C to question 360/x = 360/(x+5) +48/60 after solving this equation you will get the original speed of train i.e equal to 45 km/hr
Answers 2 Comments
Dislike Bookmark

Contact

Aditya Kumar describes himself as Mathematics. He conducts classes in Class 10 Tuition, Class 6 Tuition and Class 7 Tuition. Aditya is located in Mukherjee Nagar, Delhi. Aditya takes at students Home and Regular Classes- at his Home. He has 1 years of teaching experience . Aditya has completed Bachelor of Engineering (B.E.) from Sir MVIt in 2017. He is well versed in English and Hindi.

X
X

Post your Learning Need

Let us shortlist and give the best tutors and institutes.

or

Send Enquiry to Aditya Kumar

Let Aditya Kumar know you are interested in their class

Reply to 's review

Enter your reply*

1500/1500

Please enter your reply

Your reply should contain a minimum of 10 characters

Your reply has been successfully submitted.

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more

ThinkVidya Learning Pvt Ltd © 2010-2024All Rights Reserved