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Asked by Vikas Last Modified
Answer 
Let original speed of train = x km/h
We know,
Time = distance/speed
First case:
Time taken by train = 360/x hour
Second case:
Time taken by train its speed increase 5 km/h = 360/(x + 5)
Time taken by train in first - time taken by train in 2nd case = 48 min = 48/60 hour
360/x - 360/(x +5) = 48/60 = 4/5
360 {1/x - 1/(x +5)} = 4/5
360 ×5/4 {5/(x²+5x)}=1
450 x 5 = x² + 5x
x²+5x - 2250 = 0
x = {-5±√(25+9000)}/2
= (-5 ±√(9025))/2
=(-5 ± 95)/2
= -50, 45
But x ≠ -50 because speed doesn't negative,
So, x = 45 km/h
Hence, original speed of train = 45 km/h
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