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Overview

I graduated with my degree in chemistry and worked as Quality Control chemist in a Pharmaceutical industry for four years. I handled multiple instruments like UV, Dissolution tester, Karl Fischer Titrator, Analytical Balance and HPLC. I completed my final year project at IGCAR Kalpakkam.

Languages Spoken

Telugu Mother Tongue (Native)

English Proficient

Tamil Proficient

Education

University of Madras 2011

Bachelor of Science (B.Sc.)

University Madras 2013

Master of Science (M.Sc.)

Address

K K Nagar, Chennai, India - 600078

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Teaches

Class 6 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE, State

State boards taught

Tamil Nadu State Board

CBSE Subjects taught

Science

Taught in School or College

No

State Syllabus Subjects taught

Science

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 8 do you teach for?

CBSE and State

2. Have you ever taught in any School or College?

No

3. Which classes do you teach?

I teach Class 6 Tuition Class.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for less than a year.

Answers by Amrutha K. (2)

Answered on 18/12/2021 Learn CBSE/Class 11/Science/Chemistry/Hydrocarbons

1) The compound must have a cyclic structure. 2) The aromatic ring must be planar in order for 𝛑- electrons to be delocalized. 3) It must have a conjugated 𝛑- system. 4) It must have a p- orbitals on each atom of ring ( or sp2 or sp hybridized atoms in the ring). 5) It must have a delocalized 𝛑-... ...more

1) The compound must have a cyclic structure. 

2) The aromatic ring must be planar in order for π›‘- electrons to be delocalized.

3) It must have a conjugated π›‘- system.

4) It must have a p- orbitals on each atom of ring ( or sp2 or sp hybridized atoms in the ring).

5) It must have a delocalized π›‘- electrons in a loop of parallel overlapping p- atomic orbitals.

6) Delocalization of π›‘- electrons must lower the potential energy of a system.

 

Thus, if a molecule or ion contain monocyclic planar ring and contain (4n + 2) π›‘- electrons [Huckle rule] delocalized in a cyclic loop of parallel, overlapping p- orbitals, that molecule or ion will be called aromatic, will have unusual stability.

Answers 1 Comments
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Answered on 13/12/2021 Learn CBSE/Class 11/Science/Chemistry/Structure of Atom

Mass number (A) is the sum of the number of protons and number of neutrons present in the nucleus. A = n + p p = A - n = 13 - 7 = 6 No. of protons = no of electrons = Atomic number. Therefore the atomic number of the atom is 6
Answers 1 Comments
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Teaches

Class 6 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE, State

State boards taught

Tamil Nadu State Board

CBSE Subjects taught

Science

Taught in School or College

No

State Syllabus Subjects taught

Science

No Reviews yet!

Answers by Amrutha K. (2)

Answered on 18/12/2021 Learn CBSE/Class 11/Science/Chemistry/Hydrocarbons

1) The compound must have a cyclic structure. 2) The aromatic ring must be planar in order for 𝛑- electrons to be delocalized. 3) It must have a conjugated 𝛑- system. 4) It must have a p- orbitals on each atom of ring ( or sp2 or sp hybridized atoms in the ring). 5) It must have a delocalized 𝛑-... ...more

1) The compound must have a cyclic structure. 

2) The aromatic ring must be planar in order for π›‘- electrons to be delocalized.

3) It must have a conjugated π›‘- system.

4) It must have a p- orbitals on each atom of ring ( or sp2 or sp hybridized atoms in the ring).

5) It must have a delocalized π›‘- electrons in a loop of parallel overlapping p- atomic orbitals.

6) Delocalization of π›‘- electrons must lower the potential energy of a system.

 

Thus, if a molecule or ion contain monocyclic planar ring and contain (4n + 2) π›‘- electrons [Huckle rule] delocalized in a cyclic loop of parallel, overlapping p- orbitals, that molecule or ion will be called aromatic, will have unusual stability.

Answers 1 Comments
Dislike Bookmark

Answered on 13/12/2021 Learn CBSE/Class 11/Science/Chemistry/Structure of Atom

Mass number (A) is the sum of the number of protons and number of neutrons present in the nucleus. A = n + p p = A - n = 13 - 7 = 6 No. of protons = no of electrons = Atomic number. Therefore the atomic number of the atom is 6
Answers 1 Comments
Dislike Bookmark

Amrutha K. describes herself as Quality Control Chemist with four years experience in Pharmaceutical industry. She conducts classes in Class 6 Tuition. Amrutha is located in K K Nagar, Chennai. Amrutha takes Online Classes- via online medium. Amrutha has completed Bachelor of Science (B.Sc.) from University of Madras in 2011 and Master of Science (M.Sc.) from University Madras in 2013. SheΒ is well versed in English, Telugu and Tamil.

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