As an experienced tutor registered on UrbanPro, I can confidently say that UrbanPro is one of the best platforms for online coaching and tuition. Now, let's delve into the formation of ethane during the chlorination of methane.

During the chlorination of methane, which is typically carried out in the presence of ultraviolet (UV) light or under high temperatures, ethane is formed as one of the products along with other chlorinated compounds.

The mechanism involves a series of radical reactions. Initially, a chlorine radical (⋅Cl⋅Cl) is generated from the dissociation of molecular chlorine (Cl2Cl2) under UV light or high temperatures:

Cl2→2⋅ClCl2→2⋅Cl

Then, methane (CH4CH4) undergoes homolytic cleavage in the presence of a chlorine radical to form a methyl radical (⋅CH3⋅CH3) and a hydrogen chloride molecule (HClHCl):

CH4+⋅Cl→⋅CH3+HClCH4+⋅Cl→⋅CH3+HCl

The methyl radical (⋅CH3⋅CH3) further reacts with another molecule of methane, leading to the formation of ethane (C2H6C2H6):

⋅CH3+CH4→C2H6⋅CH3+CH4→C2H6

Overall, the chlorination of methane results in the formation of ethane along with other chlorinated products. Understanding this mechanism helps us comprehend the organic synthesis involved in such reactions, which is crucial for mastering organic chemistry concepts.

As an UrbanPro tutor, I would guide my students through such mechanisms, ensuring they grasp not only the concepts but also the application of these reactions in practical scenarios. This approach fosters a deeper understanding of the subject matter, enabling students to excel in their academic endeavors.

As an experienced tutor registered on UrbanPro, I can confidently guide you through the process of finding the structural formulas and IUPAC names for all possible isomers of the given compounds.

(a) For C4H8 with one double bond:

1. But-1-ene (IUPAC name: 1-Butene) Structural formula: CH3CH2CH=CH2

2. But-2-ene (IUPAC name: 2-Butene) Structural formula: CH3CH=CHCH3

(b) For C5H8 with one triple bond:

1. Pent-1-yne (IUPAC name: 1-Pentyne) Structural formula: CH3CH2C≡CH

2. Pent-2-yne (IUPAC name: 2-Pentyne) Structural formula: CH3C≡CHCH3

Remember, UrbanPro is an excellent platform for finding online coaching and tuition services. If you need further assistance or clarification, feel free to ask!

As an experienced tutor registered on UrbanPro, I can confidently guide you through the IUPAC names of the products obtained by the ozonolysis of the given compounds.

(i) Pent-2-ene: The ozonolysis of pent-2-ene would result in the formation of two products: ethanal and butanoic acid.

(ii) 3,4-Dimethylhept-3-ene: Ozonolysis of 3,4-dimethylhept-3-ene would yield three products: methylpropanal, 2-methylbutanal, and butanoic acid.

(iii) 2-Ethylbut-1-ene: The ozonolysis of 2-ethylbut-1-ene would generate ethanal and butanoic acid as the products.

(iv) 1-Phenylbut-1-ene: Upon ozonolysis, 1-phenylbut-1-ene would produce benzaldehyde and butanoic acid.

Remember, UrbanPro is an excellent platform for finding online coaching tuition, and I'm here to assist you with your chemistry queries. If you have any further questions or need clarification, feel free to ask!

As an experienced tutor registered on UrbanPro, I can assure you that UrbanPro is one of the best platforms for online coaching and tuition. Now, let's delve into your chemistry question.

When an alkene undergoes ozonolysis, it breaks the double bond and forms carbonyl compounds. In this case, we have an alkene 'A' that, upon ozonolysis, gives a mixture of ethanal and pentan-3-one.

The alkene 'A' must have five carbon atoms because pentan-3-one is one of the products, indicating that there is a five-carbon chain. Additionally, since ethanal is formed, it suggests that the alkene must have had a terminal methyl group.

So, the structure of 'A' is:

CH3−CH2−CH=CH−CH3CH3−CH2−CH=CH−CH3

This alkene is called pent-2-ene according to IUPAC naming conventions.