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Abhishek Singh Class I-V Tuition trainer in Bangalore

Abhishek Singh

I have 3 years of experience in this field

AECS Layout, Marathahalli, Bangalore, India - 560037.

Contact
Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

Details verified of Abhishek Singh✕

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Education

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Identity is verified based on matching the details uploaded by the Tutor with government databases.

Overview

I provide home tuition to 1st to 12th std students. I have been teaching from past 3 years.

Languages Spoken

Hindi

English

Education

National Institute of Technology (NIT), Rourkela 2015

Bachelor of Technology (B.Tech.)

Address

AECS Layout, Marathahalli, Bangalore, India - 560037

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Teaches

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

3

Board

CBSE

CBSE Subjects taught

Science, Mathematics

Taught in School or College

No

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

3

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

No

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

3

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

No

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

3

Board

CBSE

CBSE Subjects taught

Physics, Mathematics, Biology, Chemistry

Taught in School or College

No

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

3

Board

CBSE

CBSE Subjects taught

Physics, Mathematics, Biology, Chemistry

Taught in School or College

No

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 1-5 do you teach for?

CBSE

2. Have you ever taught in any School or College?

No

3. Which classes do you teach?

I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 9 Tuition, Class I-V Tuition and Class VI-VIII Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 3 years.

Contact

Answers by Abhishek Singh (4)

Answered on 18/11/2016 Learn CBSE/Class 10/Mathematics +2 Tuition/Class IX-X Tuition Linear Equations

For what value of k, do the equations 3x - y + 8 = 0 and 6x - ky = -16 represent coincident lines?

Coincident line should have same slope. So we get the equation 3/(-1) = 6/(-k). solving above equation we get k = 2;
Answers 17 Comments
Dislike Bookmark

Answered on 18/11/2016 Learn CBSE/Class 10/Mathematics +2 Tuition/Class IX-X Tuition Linear Equations

Find the solution of the pair of equations: x / 10 + y / 5 - 1 = 0 and x / 8 + y / 6 = 15?

First equation can be changed to x+2y-10 = 0 and second equation can be changed to 3x+4y-360 = 0 multiplying first equation by 4 we get 2x+4y -20 = 0 and subtracting this equation from second equation we get resulting equation as x-350 = 0.thus from this equation we get x value as 350 and putting this... ...more
First equation can be changed to x+2y-10 = 0 and second equation can be changed to 3x+4y-360 = 0 multiplying first equation by 4 we get 2x+4y -20 = 0 and subtracting this equation from second equation we get resulting equation as x-350 = 0.thus from this equation we get x value as 350 and putting this value of x in first equation we get y value as -170. Thus values are as follow: x=350 y=-170
Answers 5 Comments
Dislike Bookmark

Answered on 18/11/2016 Learn Tuition/Class XI-XII Tuition (PUC) +2 CBSE/Class 12/Mathematics Permutations

Evaluate: 8! - 3!?

8! = 40320 and 3! = 6 so 8!-3! = 40320 - 6 = 40314 thus answer is 40314
Answers 21 Comments
Dislike Bookmark

Answered on 18/11/2016 Learn Hyperbola +2 Tuition/Class XI-XII Tuition (PUC) CBSE/Class 12/Mathematics

What is the standard form of parabola?

y=ax2 + bx + c , here x2 means square of x.
Answers 37 Comments
Dislike Bookmark

Contact

Teaches

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

3

Board

CBSE

CBSE Subjects taught

Science, Mathematics

Taught in School or College

No

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

3

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

No

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

3

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

No

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

3

Board

CBSE

CBSE Subjects taught

Physics, Mathematics, Biology, Chemistry

Taught in School or College

No

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

3

Board

CBSE

CBSE Subjects taught

Physics, Mathematics, Biology, Chemistry

Taught in School or College

No

No Reviews yet!

Answers by Abhishek Singh (4)

Answered on 18/11/2016 Learn CBSE/Class 10/Mathematics +2 Tuition/Class IX-X Tuition Linear Equations

For what value of k, do the equations 3x - y + 8 = 0 and 6x - ky = -16 represent coincident lines?

Coincident line should have same slope. So we get the equation 3/(-1) = 6/(-k). solving above equation we get k = 2;
Answers 17 Comments
Dislike Bookmark

Answered on 18/11/2016 Learn CBSE/Class 10/Mathematics +2 Tuition/Class IX-X Tuition Linear Equations

Find the solution of the pair of equations: x / 10 + y / 5 - 1 = 0 and x / 8 + y / 6 = 15?

First equation can be changed to x+2y-10 = 0 and second equation can be changed to 3x+4y-360 = 0 multiplying first equation by 4 we get 2x+4y -20 = 0 and subtracting this equation from second equation we get resulting equation as x-350 = 0.thus from this equation we get x value as 350 and putting this... ...more
First equation can be changed to x+2y-10 = 0 and second equation can be changed to 3x+4y-360 = 0 multiplying first equation by 4 we get 2x+4y -20 = 0 and subtracting this equation from second equation we get resulting equation as x-350 = 0.thus from this equation we get x value as 350 and putting this value of x in first equation we get y value as -170. Thus values are as follow: x=350 y=-170
Answers 5 Comments
Dislike Bookmark

Answered on 18/11/2016 Learn Tuition/Class XI-XII Tuition (PUC) +2 CBSE/Class 12/Mathematics Permutations

Evaluate: 8! - 3!?

8! = 40320 and 3! = 6 so 8!-3! = 40320 - 6 = 40314 thus answer is 40314
Answers 21 Comments
Dislike Bookmark

Answered on 18/11/2016 Learn Hyperbola +2 Tuition/Class XI-XII Tuition (PUC) CBSE/Class 12/Mathematics

What is the standard form of parabola?

y=ax2 + bx + c , here x2 means square of x.
Answers 37 Comments
Dislike Bookmark

Contact

Abhishek Singh describes himself as I have 3 years of experience in this field. He conducts classes in Class 10 Tuition, Class 11 Tuition and Class 12 Tuition. Abhishek is located in AECS Layout, Marathahalli, Bangalore. Abhishek takes at students Home and Regular Classes- at his Home. He has 3 years of teaching experience . Abhishek has completed Bachelor of Technology (B.Tech.) from National Institute of Technology (NIT), Rourkela in 2015. He is well versed in Hindi and English.

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