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Find the solution of the pair of equations: x / 10 + y / 5 - 1 = 0 and x / 8 + y / 6 = 15?

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First equation can be changed to x+2y-10 = 0 and second equation can be changed to 3x+4y-360 = 0 multiplying first equation by 4 we get 2x+4y -20 = 0 and subtracting this equation from second equation we get resulting equation as x-350 = 0.thus from this equation we get x value as 350 and putting this...
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First equation can be changed to x+2y-10 = 0 and second equation can be changed to 3x+4y-360 = 0 multiplying first equation by 4 we get 2x+4y -20 = 0 and subtracting this equation from second equation we get resulting equation as x-350 = 0.thus from this equation we get x value as 350 and putting this value of x in first equation we get y value as -170. Thus values are as follow: x=350 y=-170 read less
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An Experienced Trainer

340, -165
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Standard form - x+2y = 10 3x+4y = 360 On solving, x = 340 & y = -165
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x=320,y=-155
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Maths teacher. Have started teaching online now

X=340, y=-165
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