Adaun, Aligarh, India - 202002.
Details verified of Tauqeer Rehan✕
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Hindi Basic
University polytechnic 2018
Diploma in Engineering
Uttar Pradesh 202002
Adaun, Aligarh, India - 202002
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
1
Board
CBSE
CBSE Subjects taught
Science, Computer Practices, Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
1
Board
CBSE
CBSE Subjects taught
Science, Computer Practices, Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
1. Which school boards of Class 10 do you teach for?
CBSE
2. Do you have any prior teaching experience?
No
3. Which classes do you teach?
I teach Class 10 Tuition, Class 9 Tuition and Engineering Entrance Coaching Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 1 year.
Answered on 17/07/2019 Learn Tuition
x^2+y^2+z^2=xy+yz+zx ----eq(1)
Identity is x^3+y^3+z^3 - 3xyz=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)
x^3+y^3+z^3 -3xyz =(x+y+z)(xy+yz+zx-xy-yz-zx) (acc. to eq1.)
Therefore , x^3+y^3+z^3 - 3xyz = 0
So, x^3+y^3+z^3= 3xyz Answer
Answered on 17/07/2019 Learn Tuition/Class IX-X Tuition
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
1
Board
CBSE
CBSE Subjects taught
Science, Computer Practices, Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
1
Board
CBSE
CBSE Subjects taught
Science, Computer Practices, Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Answered on 17/07/2019 Learn Tuition
x^2+y^2+z^2=xy+yz+zx ----eq(1)
Identity is x^3+y^3+z^3 - 3xyz=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)
x^3+y^3+z^3 -3xyz =(x+y+z)(xy+yz+zx-xy-yz-zx) (acc. to eq1.)
Therefore , x^3+y^3+z^3 - 3xyz = 0
So, x^3+y^3+z^3= 3xyz Answer
Answered on 17/07/2019 Learn Tuition/Class IX-X Tuition
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Adaun, Aligarh 
