N I B M, Pune, India - 411048.
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English
Hindi
Pune University 1997
Bachelor of Science (B.Sc.)
503, Manish Plaza, NIBM Rd, Kondhwa
N I B M, Pune, India - 411048
Landmark: Opp Brahma Majestic
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2 Students Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
5
Board
State
Taught in School or College
No
State Syllabus Subjects taught
Chemistry, Mathematics, Physics
Teaching Experience in detail in Class 12 Tuition
I have 5+ years of experience in teaching students and helping them achieve their target and make their future successful.
2 Students Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
5
Board
CBSE, State, ICSE
CBSE Subjects taught
English, Marathi, Computer Practices, Information and Comunication Technology, Science, Hindi, Mathematics
ICSE Subjects taught
Chemistry, Physics, English Literature, Computer Application, Mathematics, English, Hindi, Biology
Taught in School or College
No
State Syllabus Subjects taught
Science, Marathi, Hindi, Mathematics, English
Teaching Experience in detail in Class 10 Tuition
Helped student in achieving their with timely help as clearing their doubt, finding the way through which the student can understand easily. We make the concept of students very clear so that he can understand the topic and score good marks
2 Students Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
5
Board
State
Taught in School or College
No
State Syllabus Subjects taught
Chemistry, Mathematics, Physics
Teaching Experience in detail in Class 11 Tuition
7+ years of experience in teaching students and helping them achieve their target and make their future successful
2 Students Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
5
Board
State, ICSE
ICSE Subjects taught
Chemistry, Physics, Mathematics, Biology
Taught in School or College
No
State Syllabus Subjects taught
Science, Mathematics
Teaching Experience in detail in Class 9 Tuition
Have 7+ years of experience in teaching and helping students to achieve their targets and make their future bright.
2 Students Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
5
Fees
₹ 200.0 per hour
Board
ICSE, CBSE, State
CBSE Subjects taught
Mathematics, Science
ICSE Subjects taught
Science, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, Science
1. Which school boards of Class 12 do you teach for?
State
2. Have you ever taught in any School or College?
No
3. Which classes do you teach?
I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 9 Tuition and Class I-V Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 5 years.
Answered on 25/06/2019 Learn Tuition
Given: x2 +y2 +z2 = xy +yz +zx
We know that
x3 +y3 +z3 −3xyz = (x +y +z)(x2 +y2 +z2 −xy −yz −zx).
Substituting the value of x2 +y2 +z2 in above equation, we get
x3 +y3 +z3 −3xyz = (x +y +z)( xy +yz +zx −xy −yz −zx)
x3 +y3 +z3 −3xyz = (x +y +z) (0) …… ………………… ( xy +yz +zx −xy −yz –zx ) = 0
x3 +y3 +z3 −3xyz = 0 …………………………………………………….(x +y +z) (0) = 0
x3 +y3 +z3 = 3xyz
2 Students Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
5
Board
State
Taught in School or College
No
State Syllabus Subjects taught
Chemistry, Mathematics, Physics
Teaching Experience in detail in Class 12 Tuition
I have 5+ years of experience in teaching students and helping them achieve their target and make their future successful.
2 Students Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
5
Board
CBSE, State, ICSE
CBSE Subjects taught
English, Marathi, Computer Practices, Information and Comunication Technology, Science, Hindi, Mathematics
ICSE Subjects taught
Chemistry, Physics, English Literature, Computer Application, Mathematics, English, Hindi, Biology
Taught in School or College
No
State Syllabus Subjects taught
Science, Marathi, Hindi, Mathematics, English
Teaching Experience in detail in Class 10 Tuition
Helped student in achieving their with timely help as clearing their doubt, finding the way through which the student can understand easily. We make the concept of students very clear so that he can understand the topic and score good marks
2 Students Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
5
Board
State
Taught in School or College
No
State Syllabus Subjects taught
Chemistry, Mathematics, Physics
Teaching Experience in detail in Class 11 Tuition
7+ years of experience in teaching students and helping them achieve their target and make their future successful
2 Students Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
5
Board
State, ICSE
ICSE Subjects taught
Chemistry, Physics, Mathematics, Biology
Taught in School or College
No
State Syllabus Subjects taught
Science, Mathematics
Teaching Experience in detail in Class 9 Tuition
Have 7+ years of experience in teaching and helping students to achieve their targets and make their future bright.
2 Students Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
5
Fees
₹ 200.0 per hour
Board
ICSE, CBSE, State
CBSE Subjects taught
Mathematics, Science
ICSE Subjects taught
Science, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, Science
Answered on 25/06/2019 Learn Tuition
Given: x2 +y2 +z2 = xy +yz +zx
We know that
x3 +y3 +z3 −3xyz = (x +y +z)(x2 +y2 +z2 −xy −yz −zx).
Substituting the value of x2 +y2 +z2 in above equation, we get
x3 +y3 +z3 −3xyz = (x +y +z)( xy +yz +zx −xy −yz −zx)
x3 +y3 +z3 −3xyz = (x +y +z) (0) …… ………………… ( xy +yz +zx −xy −yz –zx ) = 0
x3 +y3 +z3 −3xyz = 0 …………………………………………………….(x +y +z) (0) = 0
x3 +y3 +z3 = 3xyz
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