Bapdev Nagar, Pimpri-Chinchwad, India - 412101.
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Hindi Mother Tongue (Native)
English Proficient
Army institute of Technology, Pune Pursuing
Bachelor of Engineering (B.E.)
Bapdev Nagar, Pimpri-Chinchwad, India - 412101
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
ICSE, CBSE, State
CBSE Subjects taught
Science, Mathematics, English
ICSE Subjects taught
English, Mathematics, Chemistry, English Literature
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, English
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
State, CBSE
CBSE Subjects taught
Chemistry, Mathematics, English
Taught in School or College
No
State Syllabus Subjects taught
Chemistry, English, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
State, CBSE
CBSE Subjects taught
Chemistry, Mathematics, English
Taught in School or College
No
State Syllabus Subjects taught
Chemistry, English, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
ICSE, CBSE, State
CBSE Subjects taught
Science, Mathematics, English
ICSE Subjects taught
English, Mathematics, Chemistry, English Literature
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, Science, English
1. Which school boards of Class 10 do you teach for?
ICSE, CBSE and State
2. Do you have any prior teaching experience?
No
3. Which classes do you teach?
I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition and Class 9 Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for less than a year.
Answered on 23/06/2019 Learn CBSE/Class 10/English
Answered on 23/06/2019 Learn Tuition
x3 + y3 + z3 – 3xyz = (x + y + z) (x2 + y2 + z2 – xy – yz – zx)
Using this equation we can get to the solution.
lets take x3 + y3 + z3 as m
then m-3xyz=(x + y + z) (x2 + y2 + z2 – xy – yz – zx)
we have to find the value of m
we know this x2 + y2 + z2 = xy+yz+zx
then the RHS becomes 0
so m=3xyz
x3 + y3 + z3 =3xyz
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
ICSE, CBSE, State
CBSE Subjects taught
Science, Mathematics, English
ICSE Subjects taught
English, Mathematics, Chemistry, English Literature
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, English
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
State, CBSE
CBSE Subjects taught
Chemistry, Mathematics, English
Taught in School or College
No
State Syllabus Subjects taught
Chemistry, English, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
State, CBSE
CBSE Subjects taught
Chemistry, Mathematics, English
Taught in School or College
No
State Syllabus Subjects taught
Chemistry, English, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
ICSE, CBSE, State
CBSE Subjects taught
Science, Mathematics, English
ICSE Subjects taught
English, Mathematics, Chemistry, English Literature
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, Science, English
Answered on 23/06/2019 Learn CBSE/Class 10/English
Answered on 23/06/2019 Learn Tuition
x3 + y3 + z3 – 3xyz = (x + y + z) (x2 + y2 + z2 – xy – yz – zx)
Using this equation we can get to the solution.
lets take x3 + y3 + z3 as m
then m-3xyz=(x + y + z) (x2 + y2 + z2 – xy – yz – zx)
we have to find the value of m
we know this x2 + y2 + z2 = xy+yz+zx
then the RHS becomes 0
so m=3xyz
x3 + y3 + z3 =3xyz
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