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Atharv Aundhekar NTSE exam trainer in Nanded

Atharv Aundhekar

Tutor

Ashoknagar, Nanded, India - 431605.

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Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

Details verified of Atharv Aundhekar

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Education

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Overview

I am a B.Tech student who has command on maths,mental ability and willing to teach. I will help you to get easy in mathematics and metal ability.

Languages Spoken

Hindi

English

Marathi

Education

SGGSIE&T, NANDED Pursuing

Bachelor of Technology (B.Tech.)

Address

Ashoknagar, Nanded, India - 431605

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Teaches

NTSE exam Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE

CBSE Subjects taught

Science, Mathematics, Marathi

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Social Science, Marathi, English, Science

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE

CBSE Subjects taught

Science, Mathematics, Marathi

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Social Science, Marathi, English, Science

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE

CBSE Subjects taught

Marathi, English, Science, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, English, Marathi, Science

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE

CBSE Subjects taught

Marathi, English, Science, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, English, Marathi, Science

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE

CBSE Subjects taught

Marathi, English, Science, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, English, Marathi, Science

National Scholarship Exam(NSE) Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Math Olympiad classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Science Olympiad classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Reviews

No Reviews yet!

FAQs

1. Which classes do you teach?

I teach Class 10 Tuition, Class 6 Tuition, Class 7 Tuition, Class 8 Tuition, Class 9 Tuition, Math Olympiad, NTSE exam Coaching, National Scholarship Exam(NSE) Coaching and Science Olympiad Classes.

2. Do you provide a demo class?

Yes, I provide a free demo class.

3. How many years of experience do you have?

I have been teaching for less than a year.

Answers by Atharv Aundhekar (5)

Answered on 08/12/2017 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

Mean of 100 observation=50 So total sum =50×100=5000 Now one observation is replaced having value 50 by 150 So change in sum=150-50=100 Therefore change in sum=100 So new sum is 5100 Therefore new mean is 5100/100=51
Answers 49 Comments
Dislike Bookmark

Answered on 08/12/2017 Learn CBSE/Class 10/Science +1 Tuition/Class IX-X Tuition

R=resistivity*lenghth/area So resistivity=R×A/L Therefore resistivity=5.026×10^-6
Answers 6 Comments
Dislike Bookmark

Answered on 05/12/2017 Learn CBSE/Class 9/Science +1 Tuition/Class IX-X Tuition

Molecular mass of O=16 and H=2 so molecular mass of H2O=18
Answers 25 Comments
Dislike Bookmark

Answered on 05/12/2017 Learn CBSE/Class 10/Science +1 Tuition/Class IX-X Tuition

Potential difference is simply the level difference between two points. In the case of charge it is measured in volts
Answers 21 Comments
Dislike Bookmark

Answered on 04/12/2017 Learn Tuition/Class IX-X Tuition

Newton's second law is simply stated as F=ma where F is the force applied m is the mass and a is acceleration
Answers 206 Comments
Dislike Bookmark

Teaches

NTSE exam Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE

CBSE Subjects taught

Science, Mathematics, Marathi

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Social Science, Marathi, English, Science

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE

CBSE Subjects taught

Science, Mathematics, Marathi

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Social Science, Marathi, English, Science

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE

CBSE Subjects taught

Marathi, English, Science, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, English, Marathi, Science

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE

CBSE Subjects taught

Marathi, English, Science, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, English, Marathi, Science

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE

CBSE Subjects taught

Marathi, English, Science, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, English, Marathi, Science

National Scholarship Exam(NSE) Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Math Olympiad classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Science Olympiad classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

No Reviews yet!

Answers by Atharv Aundhekar (5)

Answered on 08/12/2017 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

Mean of 100 observation=50 So total sum =50×100=5000 Now one observation is replaced having value 50 by 150 So change in sum=150-50=100 Therefore change in sum=100 So new sum is 5100 Therefore new mean is 5100/100=51
Answers 49 Comments
Dislike Bookmark

Answered on 08/12/2017 Learn CBSE/Class 10/Science +1 Tuition/Class IX-X Tuition

R=resistivity*lenghth/area So resistivity=R×A/L Therefore resistivity=5.026×10^-6
Answers 6 Comments
Dislike Bookmark

Answered on 05/12/2017 Learn CBSE/Class 9/Science +1 Tuition/Class IX-X Tuition

Molecular mass of O=16 and H=2 so molecular mass of H2O=18
Answers 25 Comments
Dislike Bookmark

Answered on 05/12/2017 Learn CBSE/Class 10/Science +1 Tuition/Class IX-X Tuition

Potential difference is simply the level difference between two points. In the case of charge it is measured in volts
Answers 21 Comments
Dislike Bookmark

Answered on 04/12/2017 Learn Tuition/Class IX-X Tuition

Newton's second law is simply stated as F=ma where F is the force applied m is the mass and a is acceleration
Answers 206 Comments
Dislike Bookmark

Atharv Aundhekar describes himself as Tutor. He conducts classes in Class 10 Tuition, Class 6 Tuition and Class 7 Tuition. Atharv is located in Ashoknagar, Nanded. Atharv takes Regular Classes- at his Home. Atharv is pursuing Bachelor of Technology (B.Tech.) from SGGSIE&T,NANDED. He is well versed in Hindi, English and Marathi.

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