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Post a LessonAnswered on 10 Apr Learn CBSE/Class 11/Science/Chemistry/Some Basic Concepts of Chemistry
Sadika
To convert a temperature from Fahrenheit (°F) to Celsius (°C), you can use the following formula:
C=5/9×(F−32)
Given that the measured temperature is 200°F, let's substitute this value into the formula:
C=5/9×(200−32)
C=5/9×168
C≈840/9
C≈93.33°
So, the correct answer is:
(c) 93.3°C
Answered on 10 Apr Learn CBSE/Class 11/Science/Chemistry/Some Basic Concepts of Chemistry
Sadika
To calculate the molarity (M) of a solution, you can use the formula:
First, we need to determine the number of moles of NaCl (sodium chloride) in the solution.
Number of moles=Mass/Molar mass
Number of moles=5.85 g/58.44g
Number of moles≈0.1 molNumber of moles≈0.1mol
Next, we need to convert the volume of the solution from milliliters (mL) to liters (L):
V=500 mL/1000 mL
V=0.5 L
Now, we can calculate the molarity:
M=0.1 mol/0.5 L
M=0.2 mol/L
So, the correct answer is:
(c) 0.2 mol L^-1
Answered on 10 Apr Learn CBSE/Class 11/Science/Chemistry/Some Basic Concepts of Chemistry
Sadika
To determine which element contains the greatest number of atoms, we can use the concept of molar mass and Avogadro's number.
Molar mass (M) is the mass of one mole of a substance, and Avogadro's number (Nₐ) is the number of atoms, molecules, or particles present in one mole of a substance. Avogadro's number is approximately6.022×10 23 particles/mol.
First, let's calculate the number of moles for each given mass of the elements using the formula:
Number of moles=Given massMolar massNumber of moles=Molar massGiven mass
Then, we can calculate the number of atoms for each element using the formula:
Number of atoms=Number of moles×Avogadro’s numberNumber of atoms=Number of moles×Avogadro’s number
Now, let's perform the calculations for each option:
(a) For 4g He: Number of moles=4 g4.0026 g/mol≈0.9996 molNumber of moles=4.0026g/mol4g≈0.9996mol Number of atoms=0.9996×6.022×1023≈6.027×1023Number of atoms=0.9996×6.022×1023≈6.027×1023
(b) For 46g Na: Number of moles=46 g22.9898 g/mol≈2.0003 molNumber of moles=22.9898g/mol46g≈2.0003mol Number of atoms=2.0003×6.022×1023≈1.2042×1024Number of atoms=2.0003×6.022×1023≈1.2042×1024
(c) For 0.40g Ca: Number of moles=0.40 g40.078 g/mol≈0.009978 molNumber of moles=40.078g/mol0.40g≈0.009978mol Number of atoms=0.009978×6.022×1023≈6.0085×1021Number of atoms=0.009978×6.022×1023≈6.0085×1021
(d) For 12g He: Number of moles=12 g4.0026 g/mol≈2.996 molNumber of moles=4.0026g/mol12g≈2.996mol Number of atoms=2.996×6.022×1023≈1.8026×1024Number of atoms=2.996×6.022×1023≈1.8026×1024
Comparing the calculated number of atoms for each option, we find that:
The greatest number of atoms is present in 12 g He (Option d).
Answered on 10 Apr Learn CBSE/Class 11/Science/Chemistry/Some Basic Concepts of Chemistry
Sadika
To find the molarity (M) of glucose in blood, we first need to calculate the number of moles of glucose present in 1 liter of blood, using the concentration provided.
The molar mass of glucose (C6H12O6) is calculated as follows:
Molar mass of glucose=6×Molar mass of carbon+12×Molar mass of hydrogen+6×Molar mass of oxygenMolar mass of glucose=6×Molar mass of carbon+12×Molar mass of hydrogen+6×Molar mass of oxygen
=6×12.01 g/mol+12×1.008 g/mol+6×16.00 g/mol=6×12.01g/mol+12×1.008g/mol+6×16.00g/mol
=72.06 g/mol+12.096 g/mol+96.00 g/mol=72.06g/mol+12.096g/mol+96.00g/mol
=180.156 g/mol=180.156g/mol
Given that the concentration of glucose in blood is 0.9 g/L, we can calculate the number of moles of glucose as follows:
Number of moles of glucose=MassMolar massNumber of moles of glucose=Molar massMass
=0.9 g180.156 g/mol=180.156g/mol0.9g
≈0.00499 mol/L≈0.00499mol/L
Now, to find the molarity, we divide the number of moles by the volume of the solution in liters:
Molarity (M)=Number of molesVolume (L)Molarity (M)=Volume (L)Number of moles
Molarity (M)=0.00499 mol1 LMolarity (M)=1L0.00499mol
Molarity (M)≈0.005 M
So, the correct answer is:
(c) 0.005 M
Answered on 10 Apr Learn CBSE/Class 11/Science/Chemistry/Some Basic Concepts of Chemistry
Sadika
To find the number of molecules of H2SO4H2SO4 present in 100 mL of a 0.02 M H2SO4H2SO4 solution, we need to first calculate the number of moles of H2SO4H2SO4 present in the solution using the given concentration.
Given:
Using the formula for molarity, M=molesvolume (in L)M=volume (in L)moles, we can rearrange it to find the number of moles:
moles=M×volume (in L)moles=M×volume (in L)
moles=0.02 mol/L×0.1 Lmoles=0.02mol/L×0.1L
moles=0.002 molmoles=0.002mol
Now, to find the number of molecules, we'll use Avogadro's number, 6.022×10236.022×1023 molecules/mol:
Number of molecules=moles×Avogadro’s numberNumber of molecules=moles×Avogadro’s number
Number of molecules=0.002 mol×6.022×1023 molecules/molNumber of molecules=0.002mol×6.022×1023molecules/mol
Number of molecules=1.2044×1021 moleculesNumber of molecules=1.2044×1021molecules
So, the correct answer is:
(a) 1.2044×10211.2044×1021 molecules
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