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Asked by Jacob Last Modified
Answer To find the molarity (M) of glucose in blood, we first need to calculate the number of moles of glucose present in 1 liter of blood, using the concentration provided.
The molar mass of glucose (C6H12O6) is calculated as follows:
Molar mass of glucose=6×Molar mass of carbon+12×Molar mass of hydrogen+6×Molar mass of oxygenMolar mass of glucose=6×Molar mass of carbon+12×Molar mass of hydrogen+6×Molar mass of oxygen
=6×12.01 g/mol+12×1.008 g/mol+6×16.00 g/mol=6×12.01g/mol+12×1.008g/mol+6×16.00g/mol
=72.06 g/mol+12.096 g/mol+96.00 g/mol=72.06g/mol+12.096g/mol+96.00g/mol
=180.156 g/mol=180.156g/mol
Given that the concentration of glucose in blood is 0.9 g/L, we can calculate the number of moles of glucose as follows:
Number of moles of glucose=MassMolar massNumber of moles of glucose=Molar massMass
=0.9 g180.156 g/mol=180.156g/mol0.9g
≈0.00499 mol/L≈0.00499mol/L
Now, to find the molarity, we divide the number of moles by the volume of the solution in liters:
Molarity (M)=Number of molesVolume (L)Molarity (M)=Volume (L)Number of moles
Molarity (M)=0.00499 mol1 LMolarity (M)=1L0.00499mol
Molarity (M)≈0.005 M
So, the correct answer is:
(c) 0.005 M
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