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Hariom Kumar IBPS Exam trainer in Bangalore

Hariom Kumar

Malleshpalya, Bangalore, India - 560075.

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Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

Hariom Kumar conducts classes in Class 10 Tuition, Class 11 Tuition and Class 12 Tuition. Hariom is located in Malleshpalya, Bangalore. Hariom takes at students Home and Regular Classes- at his Home. He has 1 years of teaching experience . Hariom has completed Bachelor of Technology (B.Tech.) from bput in 2013. He is well versed in Hindi, English and Oriya.

Languages Spoken

Hindi

English

Oriya

Education

bput 2013

Bachelor of Technology (B.Tech.)

Address

Malleshpalya, Bangalore, India - 560075

Verified Info

Phone Verified

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Teaches

IBPS Exam Coaching

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Hindi Language Classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Hindi Language Classes

1

Profession

Tutor

Awards and Recognition

No

Mother Tongue

No

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Reviews

No Reviews yet!

FAQs

1. Which classes do you teach?

I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 9 Tuition, Class I-V Tuition, Class VI-VIII Tuition, Hindi Language and IBPS Exam Coaching Classes.

2. Do you provide a demo class?

Yes, I provide a free demo class.

3. How many years of experience do you have?

I have been teaching for less than a year.

Contact

Answers by Hariom Kumar (3)

Answered on 20/01/2015 Learn Tuition/Class XI-XII Tuition (PUC)

Longest cell of human body?

The longest cells are neurons (nerve cells) with a length of 90cm-100cm linking the central nervous system (brain and spinal cord) to other parts of the body.
Answers 77 Comments
Dislike Bookmark

Answered on 20/01/2015 Learn Tuition/Class XI-XII Tuition (PUC)

Find the equation of the line which is equidistant from parallel lines 9x + 6y - 7 = 0 and 3x + 2y + 6 = 0.

1st line=9x+6y-7,=>6y=-9y+7=> 6y=- 9x + 7=> y=- (3/2)x + (7/6) ..... (1) Line (1) has a slope=m = - 3/2 and y-intercept = c1=7/6 2nd line : 3x + 2y + 6=0 => 2y=- 3x - 6=> y = - (3/2)x - 3 ........ (2) Line (2) has a slope = m = - 3/2 and y-intercept = c2 = - 3 A line equidistant... ...more
1st line=9x+6y-7,=>6y=-9y+7=> 6y=- 9x + 7=> y=- (3/2)x + (7/6) ..... (1) Line (1) has a slope=m = - 3/2 and y-intercept = c1=7/6 2nd line : 3x + 2y + 6=0 => 2y=- 3x - 6=> y=- (3/2)x - 3 ........ (2) Line (2) has a slope=m = - 3/2 and y-intercept = c2=- 3 A line equidistant from the two parallel lines is a line parallel to both and mid way between the two Slope of the 3rd line=m = - 3/2 y-intercept of the 3rd line=c = (c1 + c2)/2 = {(7/6) - 3}/2 = - 11/12 Hence the eqn. of this 3rd line is : y=mx + c=> y=- (3/2)x - 11/12 => 12y=- 18x - 11=> 18x + 12y + 11 = 0
Answers 14 Comments
Dislike Bookmark

Answered on 19/01/2015 Learn Tuition/Class XI-XII Tuition (PUC)

Which is the best book for teacher to prepare to teach CBSE/ICSE mathematics?

Rahul as you are in Pune if u want to study only for 11-12th then u can prefer ur text book but for competition you have K C Sinha for trigonometry, Arihant calculas, algebra.
Answers 76 Comments
Dislike Bookmark

Contact

Teaches

IBPS Exam Coaching

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Hindi Language Classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Hindi Language Classes

1

Profession

Tutor

Awards and Recognition

No

Mother Tongue

No

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

No Reviews yet!

Answers by Hariom Kumar (3)

Answered on 20/01/2015 Learn Tuition/Class XI-XII Tuition (PUC)

Longest cell of human body?

The longest cells are neurons (nerve cells) with a length of 90cm-100cm linking the central nervous system (brain and spinal cord) to other parts of the body.
Answers 77 Comments
Dislike Bookmark

Answered on 20/01/2015 Learn Tuition/Class XI-XII Tuition (PUC)

Find the equation of the line which is equidistant from parallel lines 9x + 6y - 7 = 0 and 3x + 2y + 6 = 0.

1st line=9x+6y-7,=>6y=-9y+7=> 6y=- 9x + 7=> y=- (3/2)x + (7/6) ..... (1) Line (1) has a slope=m = - 3/2 and y-intercept = c1=7/6 2nd line : 3x + 2y + 6=0 => 2y=- 3x - 6=> y = - (3/2)x - 3 ........ (2) Line (2) has a slope = m = - 3/2 and y-intercept = c2 = - 3 A line equidistant... ...more
1st line=9x+6y-7,=>6y=-9y+7=> 6y=- 9x + 7=> y=- (3/2)x + (7/6) ..... (1) Line (1) has a slope=m = - 3/2 and y-intercept = c1=7/6 2nd line : 3x + 2y + 6=0 => 2y=- 3x - 6=> y=- (3/2)x - 3 ........ (2) Line (2) has a slope=m = - 3/2 and y-intercept = c2=- 3 A line equidistant from the two parallel lines is a line parallel to both and mid way between the two Slope of the 3rd line=m = - 3/2 y-intercept of the 3rd line=c = (c1 + c2)/2 = {(7/6) - 3}/2 = - 11/12 Hence the eqn. of this 3rd line is : y=mx + c=> y=- (3/2)x - 11/12 => 12y=- 18x - 11=> 18x + 12y + 11 = 0
Answers 14 Comments
Dislike Bookmark

Answered on 19/01/2015 Learn Tuition/Class XI-XII Tuition (PUC)

Which is the best book for teacher to prepare to teach CBSE/ICSE mathematics?

Rahul as you are in Pune if u want to study only for 11-12th then u can prefer ur text book but for competition you have K C Sinha for trigonometry, Arihant calculas, algebra.
Answers 76 Comments
Dislike Bookmark

Contact

Hariom Kumar conducts classes in Class 10 Tuition, Class 11 Tuition and Class 12 Tuition. Hariom is located in Malleshpalya, Bangalore. Hariom takes at students Home and Regular Classes- at his Home. He has 1 years of teaching experience . Hariom has completed Bachelor of Technology (B.Tech.) from bput in 2013. He is well versed in Hindi, English and Oriya.

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