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A box contains 5 nails and 12 nuts. Half of the nails and half of the nuts are rusted. If one item is chosen at random then find the probability that it is rusted and is a nail?

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Mathematics Expert

first find the probability of getting a rusted and then find the probability of getting a nail!!!
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Physics and Maths made easy

The question carries an error! There are five nails and half of 5 is 2.5. It is now a meaningless assertion to say 2.5 nails (question says half of the nails and half of the nuts are rusted) are rusted. Kindly rectify the mistake and forward it once again.
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Spoken English, BTech Tuition, C Language, C++ Language, CAD etc., with 4 years of experience

5/2 nails. But doesn't make sense
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Experienced Mathematicians teacher, also can take other subjects based on requirements

P(rusted) = 8/16 P(nail) = 6/16 P(rusted and nail) = 3/16 P(A intersection B) = 8/16 + 6/16 - 3/16;
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Tutor

Half of 5 nails is not possible.
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Data Analytics & Advanced Statistics Tutor with 18 years of experience in teaching

No.of nails in box is incorrect to the second sentence in the question.
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Job experience of 1 year in an MNC, B.Tech with Diploma in Business Management

If you want you can consider the other half nail as 3rd rusty nail and proceed if you really want to consider and solve the question...!!!
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Tutor - Maths and computer science

P(rusted) = 8/16 P(nail) = 6/16 P(rusted and nail) = 3/16 P(A intersection B) = 8/16 + 6/16 - 3/16 =11/16
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Teaching is my passion!!!!

11/16
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Trainer

I think, half of the nails = 5/2 which is not appropriate, because counting nails cannot be a fraction
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