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Class 8 Tuition > Learn Class VI-VIII Tuition > What will be numbers?? _ * ( _ + _ ) = 30
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What will be numbers?? _ * ( _ + _ ) = 30

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Mathematics Tuiter

There are many solutions like 3x(5+5) = 30, or 2x (7+8 ) = 30 i.e sum of two digits must be 30/2 = 15 In other words 2x( any two digits having sum equal to 15 )
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Math magician

X = Root of 15
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Grammar Nazi

1*(0+30)=30 1*(1+29)=30 1*(2+28)=30 1*(3+27)=30 1*(4+26)=30 1*(5+25)=30 1*(6+24)=30 1*(7+23)=30 1*(8+22)=30 1*(9+21)=30 1*(10+20)=30 1*(11+19)=30 1*(12+18)=30 1*(13+17)=30 1*(14+16)=30 1*(15+15)=30 1*(16+14)=30 1*(17+13)=30 1*(18+12)=30 1*(19+11)=30 1*(20+10)=30 1*(21+9)=30 1*(22+8)=30 1*(23+7)=30 1*(24+6)=30 1*(25+5)=30 1*(26+4)=30 1*(27+3)=30 1*(28+2)=30 1*(29+1)=30 1*(30+0)=30 2*(0+15)=30 2*(1+14)=30 2*(2+13)=30 2*(3+12)=30 2*(4+11)=30 2*(5+10)=30 2*(6+9)=30 2*(7+8)=30 2*(8+7)=30 2*(9+6)=30 2*(10+5)=30 2*(11+4)=30 2*(12+3)=30 2*(13+2)=30 2*(14+1)=30 2*(15+0)=30 3*(0+10)=30 3*(1+9)=30 3*(2+8)=30 3*(3+7)=30 3*(4+6)=30 3*(5+5)=30 3*(6+4)=30 3*(7+3)=30 3*(8+2)=30 3*(9+1)=30 3*(10+0)=30 5*(0+6)=30 5*(1+5)=30 5*(2+4)=30 5*(3+3)=30 5*(4+2)=30 5*(5+1)=30 5*(6+0)=30 6*(0+5)=30 6*(1+4)=30 6*(2+3)=30 6*(3+2)=30 6*(4+1)=30 6*(5+0)=30 10*(0+3)=30 10*(1+2)=30 10*(2+1)=30 10*(3+0)=30 Solution: X*(Y+Z)=30 X...
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1*(0+30)=30 1*(1+29)=30 1*(2+28)=30 1*(3+27)=30 1*(4+26)=30 1*(5+25)=30 1*(6+24)=30 1*(7+23)=30 1*(8+22)=30 1*(9+21)=30 1*(10+20)=30 1*(11+19)=30 1*(12+18)=30 1*(13+17)=30 1*(14+16)=30 1*(15+15)=30 1*(16+14)=30 1*(17+13)=30 1*(18+12)=30 1*(19+11)=30 1*(20+10)=30 1*(21+9)=30 1*(22+8)=30 1*(23+7)=30 1*(24+6)=30 1*(25+5)=30 1*(26+4)=30 1*(27+3)=30 1*(28+2)=30 1*(29+1)=30 1*(30+0)=30 2*(0+15)=30 2*(1+14)=30 2*(2+13)=30 2*(3+12)=30 2*(4+11)=30 2*(5+10)=30 2*(6+9)=30 2*(7+8)=30 2*(8+7)=30 2*(9+6)=30 2*(10+5)=30 2*(11+4)=30 2*(12+3)=30 2*(13+2)=30 2*(14+1)=30 2*(15+0)=30 3*(0+10)=30 3*(1+9)=30 3*(2+8)=30 3*(3+7)=30 3*(4+6)=30 3*(5+5)=30 3*(6+4)=30 3*(7+3)=30 3*(8+2)=30 3*(9+1)=30 3*(10+0)=30 5*(0+6)=30 5*(1+5)=30 5*(2+4)=30 5*(3+3)=30 5*(4+2)=30 5*(5+1)=30 5*(6+0)=30 6*(0+5)=30 6*(1+4)=30 6*(2+3)=30 6*(3+2)=30 6*(4+1)=30 6*(5+0)=30 10*(0+3)=30 10*(1+2)=30 10*(2+1)=30 10*(3+0)=30 Solution: X*(Y+Z)=30 X and (Y+Z) have to be multiples of 30. read less
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Mathematician

Just ask the question properly,are the numbers must be single digit or may be double digit.If single digit there will less number of solutions like (3,4,6),(2,7,8).... and if double digit then there will number of answers like in case let a be 1 then the other two numbers must be sum of 30 so (1,29),(2,28),(3,27)......so...
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Just ask the question properly,are the numbers must be single digit or may be double digit.If single digit there will less number of solutions like (3,4,6),(2,7,8).... and if double digit then there will number of answers like in case let a be 1 then the other two numbers must be sum of 30 so (1,29),(2,28),(3,27)......so on and also be particular that the question is wether find the number of solutions ?or find solutions ? if question is about number of solutions then we must use permutations and combinations concept read less
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MATHS TRAINER FOR JEE/AEEE/KVPY/NATA AND SCHOOL TUITIONS FOR STATE BOARD & CBSE 10 YEARS EXP

let x be the real number then, x(x+x)=30 therfore x.2x =30 ,ie x^2=15, x=+square root of 15 or -square root of 15. From above sq .root15(2times sq.root 15) =30.
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Home tutor in Ramamurthy nagar

Are there any more equations available alongside this? There are three unknowns and one equation. So you cannot solve this using Algebra. You can only solve this using trial and error.
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The Best Home Tutor

infinite
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Professional Tutor with 15 years of experience.

there are many solutions
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Sanskrit tutor for cbse and sb, private

3*(5+5)=30
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Online Math Tutor for IGCSE & IB Boards with 20 years of teaching experience

there can be any multiple sets of numbers qualifying this equation. eg. 2 *( 8+7) = 30, 3 *(4+6) = 30, 10* (2+1) = 30 and many more.
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