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Asked by K Last Modified
Answer 
Tasneem
Draw a line BE parallel to AD and draw a perpendicular BF on CD.
It can be observed that ABED is a parallelogram.
BE = AD = 13 m
ED = AB = 10 m
EC = 25 − ED = 15 m
For ΔBEC,
Semi-perimeter, 
By Heron’s formula,
Area of triangle
Area of ΔBEC 
m2= 84 m2
Area of ΔBEC 
⇒ 84 = 12 × 15 × BF⇒ BF = 16815 = 11.2 m⇒ 84 = 12 × 15 × BF⇒ BF = 16815 = 11.2 m
Area of ABED = BF × DE = 11.2 × 10 = 112 m2
Area of the field = 84 + 112 = 196 m2
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A park, in the shape of a quadrilateral ABCD, has ∠ C = AB = 9 m, BC = 12 m, CD = 5 m and AD = 8 m. How much area does it occupy?
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