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Asked by Shreyas Last Modified
Answer 
Tasneem
Let ABCD be a rhombus-shaped field.
For ΔBCD,
Semi-perimeter, 
= 54 m
By Heron’s formula,
Area of triangle
Therefore, area of ΔBCD
Area of field = 2 × Area of ΔBCD
= (2 × 432) m2 = 864 m2
Area for grazing for 1 cow 
= 48 m2
Each cow will get 48 m2 area of grass field.
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let side be a ,one diagonal be 2b,2nd diagonal be 2c now ais given as 30m ,2b is given as 48m so b =24m applying pythagorus theorem a² =b² + c²,so applying this formula c=18 now area of rombus is (product of 2 diagonals) /2 two diagonals are 48m and 36m so area=(46*36)/2,no of cows are 18 so area gazed by 1 cow =(46*36)/2*18=48m².
I hope i could explain it
read lessLet PQRS be the rhombus shaped field and QS be the diagonal.
∴ area of the triangle QRS
= √ 54 × ( 54 - 30 ) ( 54 - 30 ) ( 54 - 48 )
= √ 54 × 14 × 14 × 6
= √ 2 × 3 × 3 × 3 × 7 × 2 × 7 × 2 × 3 × 2
= 2 × 3 × 7 × 2 × 3 = 252m²
∴ area of the rhombus shaped field
= 252 × 2 = 504m².
read less
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Related Questions
A park, in the shape of a quadrilateral ABCD, has ∠ C = AB = 9 m, BC = 12 m, CD = 5 m and AD = 8 m. How much area does it occupy?
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