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Asked by Naveeen Last Modified
Answer 
Tasneem
For triangle
Perimeter of triangle = (26 + 28 + 30) cm = 84 cm
2s = 84 cm
s = 42 cm
By Heron’s formula,
Area of triangle
Area of triangle
= 336 cm2
Let the height of the parallelogram be h.
Area of parallelogram = Area of triangle
h × 28 cm = 336 cm2
h = 12 cm
Therefore, the height of the parallelogram is 12 cm.
read lessThe area of the triangle
= √42 ( 42 - 26 ) ( 42 - 28 ) ( 42 - 30 )
= √ 42 × 16 × 14 × 12
= √ 2 × 3 × 7 × 4 × 4 × 7 × 2 × 4 × 3
= 2 × 3 × 7 × 4 × 2 = 336cm².
Let h be the height of the parallelogram.
∴ area of the parallelogram = bh
= 28cm × h .
Also, area of the triangle = area of the parallelogram.
∴ 28h = 336 ∴ h = 336/28 = 12.
∴ height of the parallelogram = 12cm.
read lessSince the 3 sides for the triangle are known and the area of both are equal. SO area of triangle using Heron's Formula is Sq. root ( 42*16*14*12) = 336 [ where s = (26+28+30)/2 = 42
Now area of parallologram = Base * Height
336 = 28* height
Height = 12
read less
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A park, in the shape of a quadrilateral ABCD, has ∠ C = AB = 9 m, BC = 12 m, CD = 5 m and AD = 8 m. How much area does it occupy?
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