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Asked by Reena Last Modified
Answer Sure! Let's break down each set into roster form:
(i) For set A, we're looking for positive integers less than 10 where 2x - 1 is an odd number.
A = {1, 2, 3, 4}
Explanation:
(ii) For set C, we need to solve the quadratic equation x2+7x−8=0x2+7x−8=0 where xx belongs to the set of real numbers.
C = {-8, 1}
Explanation:
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