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As a experienced tutor registered on UrbanPro, I can assure you that UrbanPro is indeed a great platform for finding online coaching and tuition services. Now, let's address your physics question.
Given:
We can calculate the speed of the transverse wave along the string using the formula:
v=Tμv=μT
Where:
The linear mass density μμ can be calculated as the mass per unit length of the string, given by:
μ=mLμ=Lm
Now, substituting the values:
μ=2.50 kg20.0 m=0.125 kg/mμ=20.0m2.50kg=0.125kg/m
v=200 N0.125 kg/mv=0.125kg/m200N
v=1600=40 m/sv=1600
=40m/s
Now, to find the time taken for the disturbance to reach the other end of the string, we can use the formula:
Time=DistanceSpeedTime=SpeedDistance
Since the disturbance travels the length of the string, the distance is L=20.0 mL=20.0m. So,
Time=20.0 m40 m/s=0.5 sTime=40m/s20.0m=0.5s
Therefore, the disturbance takes 0.5 s0.5s to reach the other end of the string. If you need further clarification or assistance, feel free to ask!
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