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Asked by Nabodit Last Modified
As an experienced tutor registered on UrbanPro, I can help you solve this physics problem. This question involves the concept of conservation of momentum. According to this principle, the total momentum before an event is equal to the total momentum after the event, provided there are no external forces acting on the system.
Here, we have a shell fired by a gun. Let's denote the mass of the shell as msms and the mass of the gun as mgmg. The muzzle speed of the shell is vsvs, and we need to find the recoil speed of the gun, denoted as vgvg.
According to the conservation of momentum:
ms⋅vs=−(mg⋅vg)ms⋅vs=−(mg⋅vg)
Given:
Let's plug these values into the equation:
0.020×80=−(100×vg)0.020×80=−(100×vg)
1.6=−100vg1.6=−100vg
Now, let's solve for vgvg:
vg=1.6−100vg=−1001.6
vg=−0.016 m/svg=−0.016m/s
Now, since the negative sign indicates direction, the recoil speed of the gun is 0.016 m/s0.016m/s in the opposite direction of the shell's motion. This means the gun moves backward with a speed of 0.016 m/s0.016m/s when the shell is fired forward with a speed of 80 m/s80m/s.
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