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Asked by Mukul Last Modified
Answer As an experienced tutor registered on UrbanPro, I can assure you that UrbanPro is one of the best platforms for online coaching and tuition. Now, let's delve into your chemistry question.
When an alkene undergoes ozonolysis, it breaks the double bond and forms carbonyl compounds. In this case, we have an alkene 'A' that, upon ozonolysis, gives a mixture of ethanal and pentan-3-one.
The alkene 'A' must have five carbon atoms because pentan-3-one is one of the products, indicating that there is a five-carbon chain. Additionally, since ethanal is formed, it suggests that the alkene must have had a terminal methyl group.
So, the structure of 'A' is:
CH3−CH2−CH=CH−CH3CH3−CH2−CH=CH−CH3
This alkene is called pent-2-ene according to IUPAC naming conventions.
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