UrbanPro

Take BTech Tuition from the Best Tutors

  • Affordable fees
  • 1-1 or Group class
  • Flexible Timings
  • Verified Tutors

Search in

Can anyone help me with the below programs: A) which returns orger summary as a list with 2- tuples. Each tuple consists of the order number and the product of the price per items and the quantity. OUTPUT: [ ('34587',163.8),('98762',284.0),('77226',98.85),('88112',74.97) ]. 10 INR should be increased in the product if the value of the order is smaller than 100.00 INR. OUTPUT: [ ('34587',163.8),('98762',284.0),(77226',108.85),('88112',84.97) ]

Asked by Last Modified  

24 Answers

Learn BTech Tuition +3 Python Python Anaconda Python Advanced

Follow 7
Answer

Please enter your answer

Build Yourself For The Future

Can't solve because product price is a part of the tuple. Since LIST IS MUTABLE so we can change its elements. We can change the whole tuple because it is an element of the list. As WKT TUPLE IS IMMUTABLE so we can't change its elements.
Comments

BCA, MCA, 11 and 12 computer science Trainer with more then 10 years of experience

Try this: t=l=len(t)t1= for i in range (l): if t<100: t1.append(,t+10)]) else: t1.append(,t)])t=t1 print(t)
Comments

Senior Software Engineer/Java Full Stack Developer.

public class DemoApplication { public static void main(String args) { //SpringApplication.run(DemoApplication.class, args); List<Order> list=new ArrayList(); list.add(new Order("34587", 163.8)); list.add(new Order("98762", 284.0)); list.add(new Order("77226", 98.85)); list.add(new Order("88112",...
read more

public class DemoApplication {

 

public static void main(String[] args) {

//SpringApplication.run(DemoApplication.class, args);

 

List<Order> list=new ArrayList();

list.add(new Order("34587", 163.8));

list.add(new Order("98762", 284.0));

list.add(new Order("77226", 98.85));

list.add(new Order("88112", 74.97));

 

System.out.println("Before Processing List orders :: "+list);

 

int index=-1;

for(Order order: list) {

index++;

if(order.getPrice()<100) {

order.setPrice(order.getPrice()+10);

list.set(index, order);

}

}

 

System.out.println("After processing List orders :: "+list);

 

}

 

}

class Order{

    private String orderNo;

    private double price;

    

    public Order(String orderNo, double price) {

super();

this.orderNo = orderNo;

this.price = price;

}

 

public void setOrderNo(String orderNo){

        this.orderNo=orderNo;

    }

    

    public String getOrderNo(){

        return orderNo;

    }

    

    public void setPrice(double price){

        this.price=price;

        

    }

    

    public double getPrice(){

        return price;

    }

 

@Override

public String toString() {

return "Order [orderNo=" + orderNo + ", price=" + price + "]";

}    

    

}

read less
Comments

I am an entrepreneur and have more than 35 years of experience in the IT industry

Pythonized my previous answer: OUTPUT = oL = oL.extend()OUTPUT = oLprint(OUTPUT)
read more

Pythonized my previous answer:

OUTPUT = [ ('34587',163.8),('98762',284.0),('77226',98.85),('88112',74.97) ]

oL = []
oL.extend([(id, price + 10) for id, price in OUTPUT if price < 100.00 or\
                  oL.append((id, price))])
OUTPUT = oL
print(OUTPUT)

read less
Comments

IT Professional with 2 years of experience

Hello Anurag, As per your question, Input:- a list of tuples with two values (order-number: string, total-order-cost: float) each Output:- the updated list of tuples. Condition: When b < 100, b = b + 10 where b: total-order-cost (product of the price per items and the quantity) for every tuple of...
read more

Hello Anurag,

As per your question,

 

Input:- a list of tuples with two values (order-number: string, total-order-cost: float) each

Output:- the updated list of tuples.

Condition: When b < 100, b = b + 10 where b: total-order-cost (product of the price per items and the quantity) for every tuple of (a, b) in the input list.

 

Program:

1) With regular for-loop:

# You might use list(input()) to read list from user input.

inputList = [('34587',163.8),('98762',284.0),('77226',98.85),('88112',74.97)]

 

outputList = []

 

for _tuple in inputList:

if (_tuple[1] < 100):

    outputList.append((_tuple[0], _tuple[1]+10))

else:

  outputList.append((_tuple[0],_tuple[1]))

print('Updated List:',outputList)

 

 

PS: Since tuples are immutable (cannot change it's value further) in python, we used one more list instead of replacing the given input list itself.

 

2) With list-comprehension:- 

inputList = [('34587',163.8),('98762',284.0),('77226',98.85),('88112',74.97)]

 

def getUpdatedList(inputList):

  return [(ele[0], ele[1]+10) if (ele[1]) < 100 else (ele[0], ele[1]) for ele in inputList]

 

outputList = getUpdatedList(inputTuple)

print(outputList)

 

Or simply,

 

print([(ele[0], ele[1]+10) if (ele[1]) < 100 else (ele[0], ele[1]) for ele in inputList]) 

 

 

Feel free to ask me any further questions. Happy Coding!!!

 

read less
Comments

IT Professional with 2 years of experience

Hello Anurag, As per your question, Input:- a list of tuples with two values (order-number: string, total-order-cost: float) each Output:- the updated list of tuples. Condition: When b < 100, b = b + 10 where b: total-order-cost (product of the price per items and the quantity) for every tuple of...
read more

Hello Anurag,

As per your question,

 

Input:- a list of tuples with two values (order-number: string, total-order-cost: float) each

Output:- the updated list of tuples.

Condition: When b < 100, b = b + 10 where b: total-order-cost (product of the price per items and the quantity) for every tuple of (a, b) in the input list.

 

Program:

1) With regular for-loop:

# You might use list(input()) to read list from user input.

inputList = [('34587',163.8),('98762',284.0),('77226',98.85),('88112',74.97)]

 

outputList = []

 

for _tuple in inputList:

if (_tuple[1] < 100):

    outputList.append((_tuple[0], _tuple[1]+10))

else:

  outputList.append((_tuple[0],_tuple[1]))

print('Updated List:',outputList)

 

 

PS: Since tuples are immutable (cannot change it's value further) in python, we used one more list instead of replacing the given input list itself.

 

2) With list-comprehension:- 

inputList = [('34587',163.8),('98762',284.0),('77226',98.85),('88112',74.97)]

 

def getUpdatedList(inputList):

  return [(ele[0], ele[1]+10) if (ele[1]) < 100 else (ele[0], ele[1]) for ele in inputList]

 

outputList = getUpdatedList(inputTuple)

print(outputList)

 

Or simply,

 

print([(ele[0], ele[1]+10) if (ele[1]) < 100 else (ele[0], ele[1]) for ele in inputList]) 

 

 

Feel free to ask me any further questions. Happy Coding!!!

 

read less
Comments

IT Professional with 2 years of experience

Hello Anurag, As per your query, Input:- a list of tuples with two values (order-number: string, total-order-cost: float) each Output:- the updated list of tuples. Condition: When b < 100, b = b + 10 where b: total-order-cost (product of the price per items and the quantity) for every tuple of (a,...
read more

Hello Anurag,

As per your query,

Input:- a list of tuples with two values (order-number: string, total-order-cost: float) each

Output:- the updated list of tuples.

Condition: When b < 100, b = b + 10 where b: total-order-cost (product of the price per items and the quantity) for every tuple of (a, b) in the input list.

Program:

1) With regular for-loop:

# You might use list(input()) to read list from user input.

inputList = [('34587',163.8),('98762',284.0),('77226',98.85),('88112',74.97)]

 

outputList = []

 

for _tuple in inputList:

if (_tuple[1] < 100): 

    outputList.append((_tuple[0], _tuple[1]+10))

else:

  outputList.append((_tuple[0],_tuple[1]))

print('Updated List:',outputList)

 

PS: Since tuples are immutable (cannot change it's value further) in python, we used one more list instead of replacing the given input list itself.

 

2) With list-comprehension:- 

inputList = [('34587',163.8),('98762',284.0),('77226',98.85),('88112',74.97)]

 

def getUpdatedList(inputList):

  return [(ele[0], ele[1]+10) if (ele[1]) < 100 else (ele[0], ele[1]) for ele in inputList]

 

outputList = getUpdatedList(inputTuple)

print(outputList)

 

Or simply,

 

print([(ele[0], ele[1]+10) if (ele[1]) < 100 else (ele[0], ele[1]) for ele in inputList])

  

 

Feel free to ask me any further questions. Happy Coding!!!

 

read less
Comments

IT Professional with 2 years of experience

Hello Anurag, As per your query, Input:- a list of tuples with two values (order-number: string, total-order-cost: float) each Output:- the updated list of tuples. Condition: When b < 100, b = b + 10 where b: total-order-cost (product of the price per items and the quantity) for every tuple of (a,...
read more

Hello Anurag,

As per your query,

Input:- a list of tuples with two values (order-number: string, total-order-cost: float) each

Output:- the updated list of tuples.

Condition: When b < 100, b = b + 10 where b: total-order-cost (product of the price per items and the quantity) for every tuple of (a, b) in the input list.

Program:

1) With regular for-loop:

# You might use list(input()) to read list from user input.

inputList = [('34587',163.8),('98762',284.0),('77226',98.85),('88112',74.97)]

 

outputList = []

 

for _tuple in inputList:

if (_tuple[1] < 100): 

    outputList.append((_tuple[0], _tuple[1]+10))

else:

  outputList.append((_tuple[0],_tuple[1]))

print('Updated List:',outputList)

 

PS: Since tuples are immutable (cannot change it's value further) in python, we used one more list instead of replacing the given input list itself.

 

2) With list-comprehension:- 

inputList = [('34587',163.8),('98762',284.0),('77226',98.85),('88112',74.97)]

 

def getUpdatedList(inputList):

  return [(ele[0], ele[1]+10) if (ele[1]) < 100 else (ele[0], ele[1]) for ele in inputList]

 

outputList = getUpdatedList(inputTuple)

print(outputList)

 

Or simply,

 

print([(ele[0], ele[1]+10) if (ele[1]) < 100 else (ele[0], ele[1]) for ele in inputList])

  

 

Feel free to ask me any further questions. Happy Coding!!!

 

read less
Comments

Btech,JEEQualified,Studied from ALLEN, Kota, deliver lectures on MATHS & SCIENCE for class 10th

Input:-a list of tuples with two values (order-number: string, total-order-cost: float) each Output:- the updated list of tuples. Condition: When b < 100, b = b + 10 where b: total-order-cost (product of the price per items and the quantity) for every tuple of (a, b) in the input list. Program: 1)...
read more

 Input:-a list of tuples with two values (order-number: string, total-order-cost: float) each Output:- the updated list of tuples.

Condition: When b < 100, b = b + 10 where b: total-order-cost (product of the price per items and the quantity) for every tuple of (a, b) in the input list. Program: 1) With regular for-loop: # You might use list(input()) to read list from user input. inputList = [('34587',163.8),('98762',284.0),('77226',98.85),('88112',74.97)]   outputList = []   for _tuple in inputList: if (_tuple[1] < 100):      outputList.append((_tuple[0], _tuple[1]+10)) else:   outputList.append((_tuple[0],_tuple[1])) print('Updated List:',outputList)  

PS: Since tuples are immutable (cannot change it's value further) in python, we used one more list instead of replacing the given input list itself.

2) With list-comprehension:-  inputList = [('34587',163.8),('98762',284.0),('77226',98.85),('88112',74.97)]   def getUpdatedList(inputList):   return [(ele[0], ele[1]+10) if (ele[1]) < 100 else (ele[0], ele[1]) for ele in inputList]   outputList = getUpdatedList(inputTuple) print(outputList)   Or simply,   print([(ele[0], ele[1]+10) if (ele[1]) < 100 else (ele[0], ele[1]) for ele in inputList])     

Feel free to ask me any further questions. enjoy coding.

read less
Comments

IT Professional Trainer with 10 years of experience in IT Industry

select orderid,productprice+10 from products where productprice<100
Comments

View 22 more Answers

Related Questions

How to prepare for interview?
Prepare your basics well.
Kothvala
What is the first step for learn supreme English?
First Start under sting tenses and then go further with small stories and learn new word daily
Vikas
Is taking a lot of tuition helpful for class 10?
Maths ,science .if you have any questions please let me know you are joining tuition. Self study mostly important but some qury difficulties guidelines also important. Best wishes
Mohammad
0 0
9
How much can i charge fr one subject if i teach btech subjects in ECE ? Rather if i provide coaching for GATE
It depends on ur teaching. Deliver demo lectures and then discuss fees as u want. If student satisfy with ur teaching he ll never denies U. Good Day
Shivani
0 0
8

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons

5G Technology & Features
What Is 5G? 5G Technology stands for 5th Generation Mobile technology. 5G mobile technology has changed the means to use cell phones within very high bandwidth. User never experienced ever before...

In This Article We Will Try To Understand Association, Aggregation, Composition, Inheritance, Generalization And Realization
i. Composition: a. What is composition? Class A contains Class B. This statement denotes a strong ownership between Class A, Where Class A is the whole and Class B is its part. In composition...
T

How to prepare for Subjects and present in Exam?
Hello, you may wonder if I say Preparing Subjects is very simple. You need to spend at least 4 hours for each Unit, each for first reading, preparing short notes, re-reading, writing on plane paper with...
S

Suresh Kumar M.

0 0
1

Starting Career in Android Development
Starting career in Android has become trouble free now. There is a lot of content available online to start learning Android. Just type “Android development” in Google and you will be flooded...

How To Prepare For Maths For IIT?
Once upon a time, a lady wanted to hire a cook for her restaurant. She interviewed many candidates and finally, she selected the one who impressed her in the interview. Lady was very impressed with his...

Recommended Articles

According to a recent survey conducted by the NCAER (National Council of Advanced Economic Research), engineering is the most sought after course in India. Some engineering courses are offered as BE or Bachelor of Engineering while some as Bachelor in Technology or B.Tech. Since engineering is a professional course, the...

Read full article >

MBA, Medicine and engineering are the three main professional courses in India. Engineering is still one of the highly sorted after professional courses in the under graduate level, while MBA is favoured as a preferred post graduate course. To shine in these courses, one needs to work and study hard. Engineering as a...

Read full article >

Appearing for exams could be stressful for students. Even though they might have prepared well, they could suffer from anxiety, tension etc. These are not good for their health and mind. However, following a few exam preparation tips can save them from all these and help them to score good marks. Let’s find out all...

Read full article >

With the current trend of the world going digital, electronic renaissance is a new movement that is welcomed by the new generation as it helps makes the lives of millions of people easier and convenient. Along with this rapidly changing movement and gaining popularity of Internet, e-Learning is a new tool that emerging...

Read full article >

Looking for BTech Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you
X

Looking for BTech Tuition Classes?

The best tutors for BTech Tuition Classes are on UrbanPro

  • Select the best Tutor
  • Book & Attend a Free Demo
  • Pay and start Learning

Take BTech Tuition with the Best Tutors

The best Tutors for BTech Tuition Classes are on UrbanPro

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more