Acharya Vihar, Bhubaneswar, India - 751013.
9
Details verified of Laxmiprava Rout✕
Identity
Education
Know how UrbanPro verifies Tutor details
Identity is verified based on matching the details uploaded by the Tutor with government databases.
English Basic
Hindi Basic
Fakir Mohan University 2019
Master of Science (M.Sc.)
Central University of Haryana 2022
Bachelor of Education (B.Ed.)
Acharya Vihar, Bhubaneswar, India - 751013
ID Verified
Phone Verified
Email Verified
Report this Profile
Is this listing inaccurate or duplicate? Any other problem?
Please tell us about the problem and we will fix it.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
1
Board
State, CBSE
CBSE Subjects taught
Chemistry, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Chemistry, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
1
Board
State, CBSE
CBSE Subjects taught
Mathematics, Science
Taught in School or College
No
State Syllabus Subjects taught
Science, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
1
Board
State, CBSE
CBSE Subjects taught
Mathematics, Science
Taught in School or College
No
State Syllabus Subjects taught
Science, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
1
Board
State, ICSE, CBSE
CBSE Subjects taught
Mathematics, Science
ICSE Subjects taught
Mathematics, Chemistry
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, Science
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 7 Tuition
1
Board
State, ICSE, CBSE
CBSE Subjects taught
Mathematics, Science
ICSE Subjects taught
Mathematics, Chemistry
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, Science
1. Which school boards of Class 12 do you teach for?
State and CBSE
2. Have you ever taught in any School or College?
No
3. Which classes do you teach?
I teach Class 10 Tuition, Class 11 Tuition, Class 7 Tuition, Class 8 Tuition and Class 9 Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a paid demo class.
5. How many years of experience do you have?
I have been teaching for 1 year.
Answered on 06/09/2019 Learn CBSE/Class 12/Mathematics/Application of Integrals/NCERT Solutions/Miscellaneous Exercise 8
Let, f(x):2Y=3X+12 ,
Y=(3X+12)/2 implies equation 1.
,g(x):4Y=3X^2 ,
Then,Y=(3X^2)/4 implies equation 2.
By comparing eq.1 and eq.2,we get
(3X^2)/4=(3X+12)/2
Then do cross multiplication,i .e.
2×(3X^2)=4×(3X+12)
6X^2=12X+48
6X^2-12X-48=0
6(X^2-2X-8)=0
X^2-2X-8=0 implies equation 3.
X^2-4X+2X-8=0
X(X-4)+2(X-4)=0
(X-4)(X+2)=0
X= 4 or -2.implies eq.4.
Putting this value in eq.1&eq.2,we have
Y=3 or 12. Implies eq.5.
Area covered by parabola and line will be=
\int [f(x)-g(x)]dx from limit a to b
=\int [(3X+12)/2]dx - \int [(3X^2)/4]dx
=[(3X^2)/4+(6X)-(3X^3)/12] from limit -2 to 4
On applying limit,we get
Area=[1/2(24+48-6+24)-1/4(64+8)]
Area=[1/2(90)-1/4(72)]
Area=45-18= 27 sq.units
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
1
Board
State, CBSE
CBSE Subjects taught
Chemistry, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Chemistry, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
1
Board
State, CBSE
CBSE Subjects taught
Mathematics, Science
Taught in School or College
No
State Syllabus Subjects taught
Science, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
1
Board
State, CBSE
CBSE Subjects taught
Mathematics, Science
Taught in School or College
No
State Syllabus Subjects taught
Science, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
1
Board
State, ICSE, CBSE
CBSE Subjects taught
Mathematics, Science
ICSE Subjects taught
Mathematics, Chemistry
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, Science
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 7 Tuition
1
Board
State, ICSE, CBSE
CBSE Subjects taught
Mathematics, Science
ICSE Subjects taught
Mathematics, Chemistry
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, Science
Answered on 06/09/2019 Learn CBSE/Class 12/Mathematics/Application of Integrals/NCERT Solutions/Miscellaneous Exercise 8
Let, f(x):2Y=3X+12 ,
Y=(3X+12)/2 implies equation 1.
,g(x):4Y=3X^2 ,
Then,Y=(3X^2)/4 implies equation 2.
By comparing eq.1 and eq.2,we get
(3X^2)/4=(3X+12)/2
Then do cross multiplication,i .e.
2×(3X^2)=4×(3X+12)
6X^2=12X+48
6X^2-12X-48=0
6(X^2-2X-8)=0
X^2-2X-8=0 implies equation 3.
X^2-4X+2X-8=0
X(X-4)+2(X-4)=0
(X-4)(X+2)=0
X= 4 or -2.implies eq.4.
Putting this value in eq.1&eq.2,we have
Y=3 or 12. Implies eq.5.
Area covered by parabola and line will be=
\int [f(x)-g(x)]dx from limit a to b
=\int [(3X+12)/2]dx - \int [(3X^2)/4]dx
=[(3X^2)/4+(6X)-(3X^3)/12] from limit -2 to 4
On applying limit,we get
Area=[1/2(24+48-6+24)-1/4(64+8)]
Area=[1/2(90)-1/4(72)]
Area=45-18= 27 sq.units
Share this Profile
Also have a look at
Reply to 's review
Enter your reply*
Your reply has been successfully submitted.
Certified
The Certified badge indicates that the Tutor has received good amount of positive feedback from Students.