Sainagar, Rajampet, India - 516115.
Details verified of Shaik Khajapeer✕
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Telugu Mother Tongue (Native)
English Basic
St.Martin's engineering college 2013
Master of Engineering - Master of Technology (M.E./M.Tech.)
Sainagar, Rajampet, India - 516115
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Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
3
Board
State, CBSE
State boards taught
Andhra Pradesh State Board
Preferred class strength
One on one/ Private Tutions
CBSE Subjects taught
Mathematics
Experience in School or College
BVN HIGH SCHOOL, Rajampet
Taught in School or College
Yes
State Syllabus Subjects taught
Mathematics
1. Which school boards of Class 10 do you teach for?
State and CBSE
2. Do you have any prior teaching experience?
Yes
3. Which classes do you teach?
I teach Class 10 Tuition Class.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 3 years.
Answered on 17 Jul Learn CBSE/Class 10/Mathematics/UNIT IV: Geometry/Constructions
First draw a line BC=6 cm.
At point B, using a proctactor measure an angle of 60º and mark a point say P.
Now join B and P and extend the line for a length of more than 5 cm.
with the help of a rounder mark point A on the line BP with a measurement of 5cm.
Now join AC.
There we have ΔABC.
Now construcy the second triangle whose sides are 3/4 th of the ΔABC.
to do that, draw a line BC which should be 3/4 times of 6cm.
BC=3/4×6 =4.5 cm and also AB=3/4×5=3.75 cm.
Repeat the above steps we used to construct the first triangle taking the new BC and AB values.
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
3
Board
State, CBSE
State boards taught
Andhra Pradesh State Board
Preferred class strength
One on one/ Private Tutions
CBSE Subjects taught
Mathematics
Experience in School or College
BVN HIGH SCHOOL, Rajampet
Taught in School or College
Yes
State Syllabus Subjects taught
Mathematics
Answered on 17 Jul Learn CBSE/Class 10/Mathematics/UNIT IV: Geometry/Constructions
First draw a line BC=6 cm.
At point B, using a proctactor measure an angle of 60º and mark a point say P.
Now join B and P and extend the line for a length of more than 5 cm.
with the help of a rounder mark point A on the line BP with a measurement of 5cm.
Now join AC.
There we have ΔABC.
Now construcy the second triangle whose sides are 3/4 th of the ΔABC.
to do that, draw a line BC which should be 3/4 times of 6cm.
BC=3/4×6 =4.5 cm and also AB=3/4×5=3.75 cm.
Repeat the above steps we used to construct the first triangle taking the new BC and AB values.
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Sainagar, Hyderabad 
