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Answered on 18 Apr Learn CBSE/Class 9/Mathematics/Algebra/Polynomials

Nazia Khanum

Problem Statement: Find the value of x2+y2x2+y2, given x+y=12x+y=12 and xy=32xy=32. Solution: Step 1: Understanding the problem We have two equations: x+y=12x+y=12 xy=32xy=32 We need to find the value of x2+y2x2+y2. Step 2: Solving the equations We'll use the method of substitution to solve... read more

Problem Statement: Find the value of x2+y2x2+y2, given x+y=12x+y=12 and xy=32xy=32.

Solution:

Step 1: Understanding the problem

  • We have two equations:
    1. x+y=12x+y=12
    2. xy=32xy=32
  • We need to find the value of x2+y2x2+y2.

Step 2: Solving the equations

  • We'll use the method of substitution to solve for xx and yy.
  • From x+y=12x+y=12, we can express yy in terms of xx as y=12−xy=12−x.
  • Substitute this expression for yy into equation 2: xy=32xy=32.
  • We get x(12−x)=32x(12−x)=32.

Step 3: Finding the values of xx and yy

  • Expanding the equation, we have 12x−x2=3212x−x2=32.
  • Rearranging terms, we get x2−12x+32=0x2−12x+32=0.
  • Now, we solve this quadratic equation for xx.
  • We can use factoring or the quadratic formula to find the values of xx.
  • Upon solving, we find two solutions for xx, let's call them x1x1 and x2x2.

Step 4: Finding corresponding values of yy

  • Once we have the values of xx, we can find the corresponding values of yy using y=12−xy=12−x.

Step 5: Calculating x2+y2x2+y2

  • For each pair of xx and yy, calculate x2+y2x2+y2.
  • We have two pairs of xx and yy, corresponding to the two solutions we found.
  • So, we calculate x12+y12x12+y12 and x22+y22x22+y22.

Step 6: Presenting the solution

  • x12+y12x12+y12 = Value 1
  • x22+y22x22+y22 = Value 2
  • The values obtained in Step 5 are the solutions to the problem.

Final Answer:

  • x2+y2=x2+y2= The sum of Value 1 and Value 2.

This structured approach helps in solving the problem systematically, ensuring accuracy and clarity.

 
 
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Answered on 18 Apr Learn CBSE/Class 9/Mathematics/Algebra/Polynomials

Nazia Khanum

Problem Analysis: Given equations: 3x+2y=123x+2y=12 xy=6xy=6 We need to find the value of 9x2+4y29x2+4y2. Solution: Step 1: Find the values of xx and yy To solve the system of equations, we can use substitution or elimination method. From equation (2), xy=6xy=6, we can express yy in terms of xx:... read more

Problem Analysis: Given equations:

  1. 3x+2y=123x+2y=12
  2. xy=6xy=6

We need to find the value of 9x2+4y29x2+4y2.

Solution:

Step 1: Find the values of xx and yy

To solve the system of equations, we can use substitution or elimination method.

From equation (2), xy=6xy=6, we can express yy in terms of xx: y=6xy=x6

Substitute this expression for yy into equation (1): 3x+2(6x)=123x+2(x6)=12

Now solve for xx:

3x+12x=123x+x12=12 3x2+12=12x3x2+12=12x 3x2−12x+12=03x2−12x+12=0

Divide the equation by 3: x2−4x+4=0x2−4x+4=0

Factorize: (x−2)2=0(x−2)2=0

So, x=2x=2.

Now, substitute x=2x=2 into equation (2) to find yy: 2y=62y=6 y=3y=3

So, x=2x=2 and y=3y=3.

Step 2: Find the value of 9x2+4y29x2+4y2

Substitute the values of xx and yy into the expression 9x2+4y29x2+4y2: 9(2)2+4(3)29(2)2+4(3)2 9(4)+4(9)9(4)+4(9) 36+3636+36 7272

Conclusion: The value of 9x2+4y29x2+4y2 is 7272.

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Answered on 18 Apr Learn CBSE/Class 9/Mathematics/Algebra/Polynomials

Nazia Khanum

Factorization of Polynomials Using Factor Theorem Introduction Factorization of polynomials is a fundamental concept in algebra that helps in simplifying expressions and solving equations. The Factor Theorem is a powerful tool that aids in factorizing polynomials. Factor Theorem The Factor Theorem... read more

Factorization of Polynomials Using Factor Theorem


Introduction

Factorization of polynomials is a fundamental concept in algebra that helps in simplifying expressions and solving equations. The Factor Theorem is a powerful tool that aids in factorizing polynomials.


Factor Theorem

The Factor Theorem states that if f(c)=0f(c)=0, then (x−c)(x−c) is a factor of the polynomial f(x)f(x).


Factorization of Polynomial x3−6x2+3x+10x3−6x2+3x+10

  1. Step 1: Find Potential Roots

    • Potential roots can be found by setting f(x)=0f(x)=0 and solving for xx.
    • Possible rational roots are determined using the Rational Root Theorem.
  2. Step 2: Test Roots Using Factor Theorem

    • Test the potential roots by substituting them into the polynomial.
    • If f(c)=0f(c)=0, then (x−c)(x−c) is a factor.
  3. Step 3: Synthetic Division

    • Perform synthetic division to divide the polynomial by the found factor.
    • Repeat the process until a quadratic polynomial is obtained.
  4. Step 4: Factorization

    • Factor the quadratic polynomial using methods like quadratic formula or decomposition.

Factorization of x3−6x2+3x+10x3−6x2+3x+10

  1. Potential Roots:

    • Potential rational roots are ±1,±2,±5,±10±1,±2,±5,±10.
  2. Testing Roots:

    • By testing, it's found that x=−2x=−2 is a root.
  3. Synthetic Division:

    • Perform synthetic division:
      (x3−6x2+3x+10)÷(x+2)(x3−6x2+3x+10)÷(x+2)

    • This yields the quotient x2−8x+5x2−8x+5.

  4. Factorization of Quotient:

    • The quadratic polynomial x2−8x+5x2−8x+5 can be factored as (x−5)(x−1)(x−5)(x−1).
  5. Final Factorization:

    • x3−6x2+3x+10=(x+2)(x−5)(x−1)x3−6x2+3x+10=(x+2)(x−5)(x−1).

Factorization of Polynomial 2y3−5y2−19y2y3−5y2−19y

  1. Potential Roots:

    • For a polynomial of the form 2y3−5y2−19y2y3−5y2−19y, potential rational roots are ±1,±12,±19,±192±1,±21,±19,±219.
  2. Testing Roots:

    • By testing, it's found that y=0y=0 is a root.
  3. Synthetic Division:

    • Perform synthetic division:
      (2y3−5y2−19y)÷y(2y3−5y2−19yy

    • This yields the quotient 2y2−5y−192y2−5y−19.

  4. Factorization of Quotient:

    • The quadratic polynomial 2y2−5y−192y2−5y−19 cannot be factored further using integer coefficients.
  5. Final Factorization:

    • 2y3−5y2−19y=y(2y2−5y−19)2y3−5y2−19y=y(2y2−5y−19).

Conclusion

Factorizing polynomials using the Factor Theorem involves identifying potential roots, testing them, performing synthetic division, and factoring the resulting quotient. This method simplifies complex expressions and aids in solving polynomial equations effectively.

 
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Answered on 02 Feb Learn CBSE/Class 9/Mathematics/Algebra/Polynomials

Pooja R. Jain

Are you seeking the best online coaching for Class 10 tuition coaching in the field of Mathematics? Look no further! UrbanPro.com is your go-to marketplace for connecting with experienced tutors and coaching institutes that specialize in Class 10 tuition coaching. Heading 1: The Problem at Hand -... read more

Are you seeking the best online coaching for Class 10 tuition coaching in the field of Mathematics? Look no further! UrbanPro.com is your go-to marketplace for connecting with experienced tutors and coaching institutes that specialize in Class 10 tuition coaching.

Heading 1: The Problem at Hand - Unraveling the Equation: Let's tackle the given mathematical problem: Compute the value of 9x² + 4y² if xy = 6 and 3x + 2y = 12. Our seasoned tutors at UrbanPro are well-equipped to guide students through such challenges.

Heading 2: Step-by-Step Solution - Navigating the Equation Maze: To solve the problem, we follow a systematic approach:

Sub-heading 1: Expressing y in terms of x:

  • Utilize the given information, xy = 6.
  • Substitute xy = 6 into the equation 3x + 2y = 12.
  • Solve for y in terms of x.

Sub-heading 2: Substitution into the Expression:

  • Once y is expressed in terms of x, substitute the value into the expression 9x² + 4y².
  • This substitution simplifies the expression and facilitates further calculations.

Sub-heading 3: Simplification and Calculation:

  • After substitution, simplify the expression and perform the necessary calculations.
  • This step-by-step approach ensures accuracy and clarity in arriving at the final result.

Heading 3: UrbanPro's Expert Tutors - Your Path to Success: Our registered tutors on UrbanPro.com are highly experienced in providing Class 10 tuition coaching. They possess the expertise to guide students through complex mathematical problems, ensuring a solid foundation in the subject.

Heading 4: Why UrbanPro for Class 10 Tuition Coaching?

  • Diverse Pool of Tutors: UrbanPro boasts a diverse pool of tutors and coaching institutes specializing in Class 10 tuition coaching, allowing students to choose the best fit for their learning style.
  • Verified and Experienced Tutors: Tutors on UrbanPro undergo a rigorous verification process, ensuring that students receive coaching from experienced and reliable educators.
  • Convenient Online Coaching: With UrbanPro, students can access top-notch Class 10 tuition coaching from the comfort of their homes, making learning more accessible and flexible.

Conclusion: Elevate Your Math Skills with UrbanPro: In conclusion, UrbanPro.com stands as a trusted marketplace connecting students with the best online coaching for Class 10 tuition coaching in Mathematics. Our experienced tutors are ready to guide you through challenging problems, ensuring academic excellence and confidence in your mathematical abilities. Unlock the door to success with UrbanPro!

 
 
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Answered on 18 Apr Learn CBSE/Class 9/Mathematics/Algebra/Polynomials

Nazia Khanum

Perimeter Calculation for Rectangle with Given Area Given Information: Area of the rectangle: 25x2−35x+1225x2−35x+12 Step 1: Determine the Dimensions To calculate the perimeter of a rectangle, we need to know its length and width. We can find these dimensions using the area provided. Step... read more

Perimeter Calculation for Rectangle with Given Area


Given Information:

  • Area of the rectangle: 25x2−35x+1225x2−35x+12

Step 1: Determine the Dimensions

To calculate the perimeter of a rectangle, we need to know its length and width. We can find these dimensions using the area provided.

Step 2: Factorize the Area

Factorize the given quadratic expression 25x2−35x+1225x2−35x+12 to find its factors, which represent the possible lengths and widths of the rectangle.

Step 3: Use Factorization to Find Dimensions

Once the quadratic expression is factorized, identify the pairs of factors that, when multiplied, give the area of the rectangle. These pairs represent possible lengths and widths.

Step 4: Calculate Perimeter

With the length and width of the rectangle known, calculate the perimeter using the formula:

Perimeter=2×(Length+Width)Perimeter=2×(Length+Width)

Step 5: Finalize

Plug in the values of length and width into the perimeter formula to obtain the final result.


Let's proceed with these steps to find the perimeter.

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