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In exam 89% of the students who appeared passed and 473 students failed. Find the total number of students who appeared for the examinations ?

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473 represents 11% students. So, 100% (total number of students) = 4300
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Pass=0.89x, x is the total students Fail=0.11x=473
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Math and Science

Given 11%=473 =>1%=473/11 =>100%=(473/11)*100=4300
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Best Institute For Competitive Exams

Pass=0.89x, x is the total students Fail=0.11x=473
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CSIR NET,UGC NET, GMAT, BANK P.O.,IIT FOUNDATION COURSE, QUANTITATIVE APTITUDE Etc.

4300
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Engineering Professional & Trainer with more than 20 Years of Teaching Experience

The answer is simple total number appeared is 3827 and total number of student is 4300. Therefore (3827)/(4300)*100=89% Answer: Let x be the total number of passed, and 473 is failed Therefore x/x+473=0.89, Now x=3827, Total number of student x+437 i.e 4300
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8+ years of experience working in MNC in Software testing . Also Certified Business analyst

let the number of students be x , so as per question - x-89%of x=473, now just find the value of x
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No. of Students = 473*100/11 = 4300
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Cracking CAT and other MBA exams

Let total number of student who appeared in exam = X Now, 11% of X = 473 so, X = 4300
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4300
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