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Asked by Abhishek Last Modified
Answer First, let's find the perimeter of the rectangle, which is equal to the length of the wire:
Perimeter of the rectangle = 2 * (length + breadth) = 2 * (40 cm + 22 cm) = 2 * 62 cm = 124 cm
Since the wire is bent to form a square, the perimeter of the square will also be 124 cm.
Now, let's find the measure of each side of the square:
Perimeter of the square = 4 * side
So, 4 * side = 124 cm
Dividing both sides by 4:
side = 124 cm / 4 = 31 cm
Each side of the square will measure 31 cm.
Now, let's find the area enclosed by each shape:
Area of the rectangle = length * breadth = 40 cm * 22 cm = 880 cm²
Area of the square = side * side = 31 cm * 31 cm = 961 cm²
Comparing the two areas, we find that the square encloses more area than the rectangle.
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