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Perimeter and Area

Perimeter and Area relates to CBSE/Class 7/Maths

Top Tutors who teach Perimeter and Area

1
Indira S. Class 7 Tuition trainer in Papanasam Featured
Arundavapuram, Papanasam
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15 yrs of Exp
450per hour
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understanding the students requirement and tutoring the student from where the student is in subject what he/she learning.

2
Ottapalam, Ottapalam
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15 yrs of Exp
400per hour
Classes: Class 7 Tuition, Class 12 Tuition and more.

I am a resident of Kerala working in a CBSE school.I got the opportunity of working with Kendreya Vidyalaya (Ottapalam) , Cambridge Public School...

3
Ranjan Kumar K Class 7 Tuition trainer in Mahabubnagar Featured
Mahabubnagar, Mahabubnagar
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9 yrs of Exp
300per hour
Classes: Class 7 Tuition, Class 8 Tuition and more.

I am a B.Tech graduate. I completed my graduation in 2007. Because of passion for Teaching I entered in Teaching field. I have been teaching since...

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Akshay Aggarwal Class 7 Tuition trainer in Delhi Featured
Badarpur, Delhi
Super Tutor
8 yrs of Exp
750per hour
Classes: Class 7 Tuition, Class 11 Tuition and more.

Teaching since 8 years

5
Deepak Joshi Class 7 Tuition trainer in Gurgaon Featured
Sec-66, Gurgaon
Super Tutor
10 yrs of Exp
800per hour
Classes: Class 7 Tuition, Class 12 Tuition and more.

Ph.D candidate with over 10 years of teaching exp. (7 years at BYJU's & 3 years at a IB/IGCSE school). Specialized in IB, IGCSE, CBSE & ICSE cu...

6
Bhawana Gupta Class 7 Tuition trainer in Budaun Featured
Ujhani, Budaun
Super Tutor
6 yrs of Exp
350per hour
Classes: Class 7 Tuition, Class 9 Tuition and more.

I am a TGT Maths teacher. I am giving online tution since 2019. I am certified in B.ed(Maths and Science). My key skills are problem solving, creativity...

7
Jaikumar Veerwani Class 7 Tuition trainer in Surat Featured
Adajan Adajan Gam, Surat
Super Tutor
6 yrs of Exp
250per hour
Classes: Class 7 Tuition, Class 8 Tuition and more.

I would provide students with notes pdf and various things helping to boost academics

8
Debabrato Chatterjee Class 7 Tuition trainer in Thane Featured
Thane West, Thane
Super Tutor
15 yrs of Exp
200per hour
Classes: Class 7 Tuition, Class 10 Tuition and more.

This is Debabrato Chatterjee online Maths and Science tutor having 13+years of experience. I have already and presently teaching students of IB,...

9
Shivam Pandey Class 7 Tuition trainer in Delhi Featured
Laxmi Nagar Vishwakarma Park, Delhi
Super Tutor
6 yrs of Exp
300per hour
Classes: Class 7 Tuition, Vedic Maths Training and more.

As a mathmatics teacher what I found in class 7 students can storng their basics because they have enough time here to learn properly . Here they...

10
Aditya Pratap Singh . Class 7 Tuition trainer in Lucknow Featured
Lalkuan, Lucknow
Top Tutor
3 yrs of Exp
300per hour
Classes: Class 7 Tuition, Class 10 Tuition and more.

I have a three years of experience teaching in filo edtech . Class 6 to 10 students, I specialize in Mathematics, Science and Social Studies. My...

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Perimeter and Area Questions

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Answered on 07 Mar Learn CBSE/Class 7/Maths/Perimeter and Area

Sadika

To find the area of a square with a side length of 16.5 decameters (dam) in square meters: Area = side^2 = (16.5 dam)^2 = 16.5^2 dam^2 = 272.25 m^2 So, the area of the square is 272.25 square meters. read more

To find the area of a square with a side length of 16.5 decameters (dam) in square meters:

Area = side^2 = (16.5 dam)^2 = 16.5^2 dam^2 = 272.25 m^2

So, the area of the square is 272.25 square meters.

 
 
 
 
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Answered on 07 Mar Learn CBSE/Class 7/Maths/Perimeter and Area

Sadika

To find the area of a rectangular field in acres with sides of 200 meters and 125 meters: Then, we convert the area from square meters to acres. Since 1 acre is equal to 4046.86 square meters: So, the area of the rectangular field is approximately 6.18 acres. read more

To find the area of a rectangular field in acres with sides of 200 meters and 125 meters:

Then, we convert the area from square meters to acres. Since 1 acre is equal to 4046.86 square meters:

So, the area of the rectangular field is approximately 6.18 acres.

 
 
 
 
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Answered on 07 Mar Learn CBSE/Class 7/Maths/Perimeter and Area

Sadika

To find the cost of painting the wall, we first need to calculate the area of the wall excluding the area covered by the door, and then multiply it by the cost per square meter. Calculate the cost: Cost per square meter = Rs 2.50Total cost = Area of the wall excluding the door × Cost per square... read more

To find the cost of painting the wall, we first need to calculate the area of the wall excluding the area covered by the door, and then multiply it by the cost per square meter.

Calculate the cost:

  • Cost per square meter = Rs 2.50
    Total cost = Area of the wall excluding the door × Cost per square meter

    So, the cost of painting the wall is Rs 235.

     
     
     
     
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Answered on 07 Mar Learn CBSE/Class 7/Maths/Perimeter and Area

Sadika

First, let's find the perimeter of the rectangle, which is equal to the length of the wire: Perimeter of the rectangle = 2 * (length + breadth) = 2 * (40 cm + 22 cm) = 2 * 62 cm = 124 cm Since the wire is bent to form a square, the perimeter of the square will also be 124 cm. Now, let's find... read more

First, let's find the perimeter of the rectangle, which is equal to the length of the wire:

Perimeter of the rectangle = 2 * (length + breadth) = 2 * (40 cm + 22 cm) = 2 * 62 cm = 124 cm

Since the wire is bent to form a square, the perimeter of the square will also be 124 cm.

Now, let's find the measure of each side of the square:

Perimeter of the square = 4 * side

So, 4 * side = 124 cm

Dividing both sides by 4:

side = 124 cm / 4 = 31 cm

Each side of the square will measure 31 cm.

Now, let's find the area enclosed by each shape:

Area of the rectangle = length * breadth = 40 cm * 22 cm = 880 cm²

Area of the square = side * side = 31 cm * 31 cm = 961 cm²

Comparing the two areas, we find that the square encloses more area than the rectangle.

 
 
 
 
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Answered on 07 Mar Learn CBSE/Class 7/Maths/Perimeter and Area

Sadika

To find the total area of glass required for 12 panes, we first find the area of one pane and then multiply it by the number of panes. Area of one pane = Length × Breadth = 25 cm × 16 cm = 400 cm² Now, we have to convert the area from square centimeters to square meters,... read more

To find the total area of glass required for 12 panes, we first find the area of one pane and then multiply it by the number of panes.

Area of one pane = Length × Breadth = 25 cm × 16 cm = 400 cm²

Now, we have to convert the area from square centimeters to square meters, as 1 square meter equals 10,000 square centimeters.

So, 400 cm² = 400 / 10,000 m² ≈ 0.04 m²

Therefore, the area of one pane is approximately 0.04 square meters.

To find the total area required for 12 panes, we multiply the area of one pane by the number of panes:

Total area = Area of one pane × Number of panes = 0.04 m² × 12 = 0.48 m²

So, 0.48 square meters of glass will be required for 12 panes.

 
 
 
 
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