Sector 137 Paras Tierea, Noida, India - 201304
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GF-11,Commerical-1,Gate-2 Paras Tierea,
-Sector 137, Noida, Uttar Pradesh 201301
Sector 137 Paras Tierea, Noida, India - 201304
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Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
CBSE
CBSE Subjects taught
Mathematics, Chemistry, Economics, Physics, Accountancy
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
CBSE
CBSE Subjects taught
Mathematics, Chemistry, Economics, Physics, Accountancy
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Engineering Entrance Exams
GATE Coaching Classes
Type of class
Regular Classes, Crash Course
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
CBSE
CBSE Subjects taught
Science, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
CBSE
CBSE Subjects taught
Science, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
CBSE
CBSE Subjects taught
Science, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
CBSE
CBSE Subjects taught
Mathematics, Science, Hindi
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
BSc Branch
BSc Mathematics
BSc Mathematics Subjects
Probability and Statistics, Algebra
1. Which school boards of of Class 11 do you teach for?
CBSE
2. Which classes do you teach?
We teach BSc Tuition, Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 7 Tuition, Class 8 Tuition, Class 9 Tuition, Engineering Entrance Coaching, Math Olympiad and NTSE exam Coaching Classes
3. Do you provide a demo class?
Yes, We provide a free demo class.
4. Where are you located?
We are located in Sector 137 Paras Tierea, Noida.
Answered on 18/06/2020 Learn CBSE/Class 11/English/English - Hornbill - Reading Skills/Discovering Tut: the Saga Continues
Answered on 18/06/2020 Learn CBSE/Class 11
∫log x dx = x log x -x
Proof : Using integration by parts,
∫udv = uv - ∫vdu
In ∫ log x dx,
take, u=logx => du= (1/x) . dx
∫dv=∫dx => v=x
Now substituting,
∫log x = logx (x) - ∫x . 1/x . dx = logx (x) - ∫dx= x log x -x + C
where C is constant.
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
CBSE
CBSE Subjects taught
Mathematics, Chemistry, Economics, Physics, Accountancy
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
CBSE
CBSE Subjects taught
Mathematics, Chemistry, Economics, Physics, Accountancy
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Engineering Entrance Exams
GATE Coaching Classes
Type of class
Regular Classes, Crash Course
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
CBSE
CBSE Subjects taught
Science, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
CBSE
CBSE Subjects taught
Science, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
CBSE
CBSE Subjects taught
Science, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
CBSE
CBSE Subjects taught
Mathematics, Science, Hindi
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
BSc Branch
BSc Mathematics
BSc Mathematics Subjects
Probability and Statistics, Algebra
Answered on 18/06/2020 Learn CBSE/Class 11/English/English - Hornbill - Reading Skills/Discovering Tut: the Saga Continues
Answered on 18/06/2020 Learn CBSE/Class 11
∫log x dx = x log x -x
Proof : Using integration by parts,
∫udv = uv - ∫vdu
In ∫ log x dx,
take, u=logx => du= (1/x) . dx
∫dv=∫dx => v=x
Now substituting,
∫log x = logx (x) - ∫x . 1/x . dx = logx (x) - ∫dx= x log x -x + C
where C is constant.
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