Dhantoli, Nagpur, India - 440010.
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RASHTRASANT TUKADOJI MAHARAJ NAGPUR UNIVERSITY 2018
Master of Science (M.Sc.)
Dhantoli, Nagpur, India - 440010
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE
CBSE Subjects taught
Mathematics, English, Science
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE
CBSE Subjects taught
Mathematics, English, Science
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE
CBSE Subjects taught
Mathematics, English, Science
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
State, CBSE
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, Science, English
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
State, CBSE
CBSE Subjects taught
English, Mathematics, Science, Hindi
Taught in School or College
No
State Syllabus Subjects taught
Hindi, Mathematics, Science, English
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
State, CBSE
Taught in School or College
No
State Syllabus Subjects taught
Physics, Mathematics, English, Chemistry, Biology
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
BSc Physics Subjects
Electromagnetic Theory, Solid State Physics
Type of class
Regular Classes, Crash Course
Class strength catered to
One on one/ Private Tutions, Group Classes
Taught in School or College
No
BSc Branch
BSc Physics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
State, CBSE
CBSE Subjects taught
Mathematics, English, Physics, Chemistry
Taught in School or College
No
State Syllabus Subjects taught
Physics, Mathematics, English, Chemistry, Biology
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
State, CBSE
CBSE Subjects taught
English, Hindi, EVS, Mathematics, Science
Taught in School or College
No
State Syllabus Subjects taught
Science, EVS, Mathematics, Hindi, English, Social Science
1. Which school boards of Class 8 do you teach for?
CBSE
2. Have you ever taught in any School or College?
No
3. Which classes do you teach?
I teach BSc Tuition, Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 6 Tuition, Class 7 Tuition, Class 8 Tuition, Class 9 Tuition and Class I-V Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for less than a year.
Answered on 28/11/2018 Learn CBSE/Class 11/Science/Chemistry/Equilibrium
disassociation of acetic acid takes place as acetate ions (CH3COO-) and hydrogen ions (H+)
CH3COOH ⇔CH3COO- + H+
given: disassociation or ionization constant , K=1.74 ×10 -5
concentration, C =0.05 M
So,degree of disassociation or concentration of acetate ions (α) is
K=α2C ⇒α =√(K/C)
α =√(1.74 ×10-5/0.05) =√ 0.000348=0.01865
also ,[H+] =αC =0.01865 ×0.05=9.325×10-4
So pH = -log10[H+]= -log10(9.325×10-4)=3.03
Hence ,pH of solution is 3.03
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE
CBSE Subjects taught
Mathematics, English, Science
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE
CBSE Subjects taught
Mathematics, English, Science
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE
CBSE Subjects taught
Mathematics, English, Science
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
State, CBSE
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, Science, English
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
State, CBSE
CBSE Subjects taught
English, Mathematics, Science, Hindi
Taught in School or College
No
State Syllabus Subjects taught
Hindi, Mathematics, Science, English
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
State, CBSE
Taught in School or College
No
State Syllabus Subjects taught
Physics, Mathematics, English, Chemistry, Biology
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
BSc Physics Subjects
Electromagnetic Theory, Solid State Physics
Type of class
Regular Classes, Crash Course
Class strength catered to
One on one/ Private Tutions, Group Classes
Taught in School or College
No
BSc Branch
BSc Physics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
State, CBSE
CBSE Subjects taught
Mathematics, English, Physics, Chemistry
Taught in School or College
No
State Syllabus Subjects taught
Physics, Mathematics, English, Chemistry, Biology
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
State, CBSE
CBSE Subjects taught
English, Hindi, EVS, Mathematics, Science
Taught in School or College
No
State Syllabus Subjects taught
Science, EVS, Mathematics, Hindi, English, Social Science
Answered on 28/11/2018 Learn CBSE/Class 11/Science/Chemistry/Equilibrium
disassociation of acetic acid takes place as acetate ions (CH3COO-) and hydrogen ions (H+)
CH3COOH ⇔CH3COO- + H+
given: disassociation or ionization constant , K=1.74 ×10 -5
concentration, C =0.05 M
So,degree of disassociation or concentration of acetate ions (α) is
K=α2C ⇒α =√(K/C)
α =√(1.74 ×10-5/0.05) =√ 0.000348=0.01865
also ,[H+] =αC =0.01865 ×0.05=9.325×10-4
So pH = -log10[H+]= -log10(9.325×10-4)=3.03
Hence ,pH of solution is 3.03
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