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Asked by Reap Last Modified
Answer 
disassociation of acetic acid takes place as acetate ions (CH3COO-) and hydrogen ions (H+)
CH3COOH ⇔CH3COO- + H+
given: disassociation or ionization constant , K=1.74 ×10 -5
concentration, C =0.05 M
So,degree of disassociation or concentration of acetate ions (α) is
K=α2C ⇒α =√(K/C)
α =√(1.74 ×10-5/0.05) =√ 0.000348=0.01865
also ,[H+] =αC =0.01865 ×0.05=9.325×10-4
So pH = -log10[H+]= -log10(9.325×10-4)=3.03
Hence ,pH of solution is 3.03
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